//仿照教材p198页面，声明包含10个元素的Point对象数组，并计算距离最大两点之间的距离。
#include <iostream>
#include <cmath>
using namespace std;

class Point
{
    public:
        Point(float x=0,float y=0):x(x),y(y){}
        
        float getX() const
        {
            return x;
        }
        float getY() const
        {
            return y;
        }
   
    private:
        float x,y;
};

float distance(const Point points[],int nPoint)
{
    int i,j,k;
    int length[100];
    float x,y;
    float max=length[0];
   
for(k=0;k<100;k++)
{
    for(i=0;i<nPoint;i++)
    {
        for(j=0;(j!=i)&&j<nPoint;j++)
        {
        
            x=points[i].getX()-points[j].getX();
            y=points[i].getY()-points[j].getY();
            length[k]=sqrt(x*x+y*y);
        }        
    }
   
    if(max<length[k])
    max=length[k];
}

return max;
}

int main()
{
    Point p[10]={Point(1,2),Point(2,3),Point(3,4),Point(4,5),Point(5,6),Point(6,7),Point(7,8),Point(8,9),Point(9,10),Point(10,11)};
    float len=distance(p,10);
    cout<<"the max distance is:"<<len<<endl;
    return 0;
}

sizeof(length)/sizeof(float)是什么意思？