#include<stdio.h>
int main()
{
void hanoi(int n,char one,char two,char three);
int m;
printf("input the number of disks:");
scanf("%d",&m);
printf("The step to move %d disks:\n",m);
hanoi(m,'A','B','C');
//return 0;
}

void hanoi(int n,char one,char two,char three)
{
void move(char x,char y);
if (n==1)
move(one,three);
else
{
    hanoi(n-1,one,three,two);
    move(one,three);
    hanoi(n-1,two,one,three);
}
}

void move(char x,char y)
{
printf("%c->%c\n",x,y);
}


注不注释掉return都能运行，为什么啊？
求前辈解答！

#include<stdio.h>
int main()
{

int m;
printf("input the number of disks:");
scanf("%d",&m);
printf("The step to move %d disks:\n",m);

//return 0;
}
只看这个也行..