题目：将10元钱兑换成1元，5角，1角的硬币，共40枚，计算有多少种兑换方法。并且求出最小枚数的组合，和最大枚数的组合。

#include<stdio.h>
void main()
{
    int x,y,z,j=0,a[5],min，max=0;
        for(x=0;x<=10;x++)
        for(y=0;y<=20;y++)
        {z=40-x-y;
        if(10*x+5*y+z==100)
        {
            j=j+1;
            a[j]=x+y+z;
            min=a[1];
            printf("di %d zhong fangfa:1 yuan%dmei,5jiao%dmei,1jiao%dmei\n",j,x,y,z);
        }
        }
        if(a[j]<min)
            min=a[j];
                if(a[j]>max)
                  max=a[j]
        printf("gong you%d zhong ruihuan fanfang\n",j);
        printf("zui xiao/da de zuhe fangfa si wei:%d,&d,x=%d,y=%d,z=%d",min,max,x,y,z);
}
#include<stdio.h>
void main()
{
    int x,y,z,j=0,a[5],min;
        for(x=0;x<=10;x++)
        for(y=0;y<=20;y++)
        {z=40-x-y;
        if(10*x+5*y+z==100)
        {
            j=j+1;
            a[j]=x+y+z;
            min=a[1];
            printf("di %d zhong fangfa:1 yuan%dmei,5jiao%dmei,1jiao%dmei\n",j,x,y,z);
        }
        }
        if(a[j]<min)
            min=a[j];
        printf("gong you%d zhong ruihuan fanfang\n",j);
        printf("zui xiao de zuhe fangfa si wei:%d,x=%d,y=%d,z=%d",min,x,y,z);
}
我这代码有错误，求指出.

[ 本帖最后由 叶舞秋风 于 2014-7-19 10:59 编辑 ]

大神，你帮我改过来啊，这说的我有点蒙。

要怎么保存它的值，你别只纸上谈兵啊