#include<stdio.h>
#include<math.h>

int main(void)
{
     int a,x,number,y,z,j;
     float b;
     double m,n;
     long int i;
     printf("Please enter a number but no larger than 10 digits:");
     scanf_s("%d",&a);
     number=0;
     n=10;

     for (i=1;i<=a;i=i*10)//count number of digitals
     {
         number=number+1;
     }
     z=number;

     for (j=z;j>0;j--)
     {   
         m=j-1;
         x=pow(n,m);
         b=a/x;
         y=(int)b;
         switch (y)
     {
        case 0: // if y=0
            printf("zero"); // print zero
            break; // terminate
        case 1: // if y=1
            printf("one"); // print one
            break; // terminate
        case 2: // if y=2
            printf("two"); // print two
            break; // terminate
        case 3: // if y=3
            printf("three"); // print three
            break; // terminate
        case 4: // if y=4
            printf("four"); // print four
            break; // terminate
        case 5: // if y=5
            printf("five"); // print five
            break; // terminate
        case 6: // if y=6
            printf("six"); // print six
            break; // terminate
        case 7: // if y=7
            printf("seven"); // print seven
            break; // terminate
        case 8: // if y=8
            printf("eight"); // print eight
            break; // terminate
        case 9: // if y=9
            printf("nine"); // print nine
            break; // terminate
         }
            a=a-y*x;
            if (j>1)
                printf("-");
            else
                printf(" ");
            
     }
     printf("\n");
     return 0;
}




十位数字一下都可以就是不知道为什么每次到十位数字就出错。
找不到问题。。。。

前两个没问题，第三句话我不是很懂。我刚接触c不到一个月。是说int不能表示这个数字吗？ 所以用long int?

已解决，谢谢