#include <stdio.h>
#include <stdlib.h>


#define QUIT 4


int get_menu_choice(void);


int main()
{
    int choice = 0;
    int int_var = 0;
    float float_var = 0.0;
    unsigned  unsigned_var = 0;


    while(choice != QUIT)
    {
        choice = get_menu_choice();

        if (choice == 1)
        {
            puts("\nEnter a signed decimal integer  (i.e.-123)");
            scanf("%d",&int_var);
        }
        if(choice == 2)
        {
            puts("\nEnter a decimal floating-point number (e.g.1.23)");
            scanf("%f",&float_var);
        }
        if (choice == 3);
        {
            puts("\nEnter an unsigned decimal integer  (e.g.1.23)");//为什么这一行总是出现？
            scanf("%u",&unsigned_var);
        }
    }
    printf("\nYour values are:int:%d,float:%f,unsigned:%u\n ",int_var,float_var,unsigned_var);

    return 0;
}





int get_menu_choice(void)
{
    int selection = 0;

    do
    {
        puts("\n1-Get a signed decimal integer");
        puts("\n2-Get a decimal flosting-point number");
        puts("\n3-Get a unsigned decimal integer");
        puts("\n4-Quit");
        puts("Enter a selection:");


        scanf("%d",&selection);

        }
        while (selection < 1 ||selection >4);

        return (selection);
}



上面是程序，看了好几遍都感觉没有错误，但是运行的时候不论输入1还是2做标记的那一行总是出现，用的是CodeBlocks编译的，怀疑是不是编译器有问题

编译器是CodeBlocks10.05

弄错了，多了一个  ;

又运行了一次程序，突然间就看到了...