谁能帮忙看下这个代码是哪儿错了为什么完全得不到想要的结果？？？？
就连第一个函数N1=[a/2][b/2]得到的结果也不对？？[a/2][b/2]代表两个数除以2取整相乘得到整数。
程序代码：#include<stdio.h>
#include<math.h>
int no1(double a,double b);
int no2(double a,double b);
int no3(double a,double b);
main(){
double a,b;
printf("请输入矩形的长和宽：\n");
scanf("%lf,%lf\n",&a,&b);
printf("方案一可获得圆盘个数为：%d\n",no1(a,b));
printf("方案二可获得圆盘个数为：%d\n",no2(a,b));
if(a==b)
printf("方案三可获得圆盘个数为：%d\n",no3(a,b));
}
int no1(double a,double b){
int n1;
n1=（int）floor(a/2.0)*floor(b/2.0);
return n1;
}
int no2(double a,double b){
int n2,m;
m=(int)floor((a-2)/pow(3,0.5))+1;
if((int)floor(b)/2==0&&m%2!=0)
n2=m*(floor(b)-1)/2+1/2;
if(m%2==0)
n2=m*(floor(b)-1)/2;
return n2;
}
int no3(double a,double b){
int n3,n31,n32,m1;
double b1;
b1=floor((3/10)*a);
n31=floor(a/2)*floor(b1/2);
m1=(int)floor((a-2)/pow(3,0.5))+1;
if(floor(a)/2==0)
n32=m1*(floor(a)-1)/2+1/2;
else
n32=m1*(floor(a)-1)/2;
n3=n31+n32-floor(a);
return n3;
}
