这个地方不理解了
1.
程序代码：
1 #include<stdio.h>
2
3 #define molecular 3.0e-23;
4 #define quart 950;
5
6 int main(void)
7 {
8 int quart_count;
9 double count;
10 printf("please input how many quart water:");
11 scanf("%d",&quart_count);
12 count =quart_count*quart/molecular;
13 printf("these water cotains %e molecular",count);
14 return 0;
15 } 2.
程序代码：
1 #include<stdio.h>
2
3 #define molecular 3.0e-23;
4 #define quart 950;
5
6 int main(void)
7 {
8 int quart_count;
9 double count;
10 printf("please input how many quart water:");
11 scanf("%d",&quart_count);
12 count =quart_count*quart;
13 count = count/molecular;
14 printf("these water cotains %e molecular",count);
15 return 0;
16 }
方案一居然提示
61.c: 在函数‘main’中:
61.c: 12:26: 错误：expected expression before ‘/’ token
count =quart_count*quart/molecular;
方案二顺利通过
这我就不能理解了，大神，何解？
我是用的是win7 64下的cygwin gcc编译
