题目是计算给定金额的货币数量，比如$11.56处理后为11个一美元，2个25美分，和1个十美分还有一美分。
 下面试代码

#include<iostream>
using namespace std;

int main()
{
        cout<<"enter an aomunt in double ,for example 11.56 :";
        double amount;
        cin>>amount;
        // remainingAmount用来保留运算后的剩余的货币金额
        int remainingAmount = static_cast<int>(amount * 100);
        // "/"计算当前最大面值，“%”求未表示出的金额数（即被忽略的金额）

int numberOfOneDollars = remainingAmount / 100;
        remainingAmount  =remainingAmount % 100;
        
        int numberOfQuarters = remainingAmount / 25;
        remainingAmount = remainingAmount % 25;
        
        int numberOfDimes =remainingAmount / 10;
        remainingAmount = remainingAmount % 10;
        
        int numberOfNickels = remainingAmount / 5;
        remainingAmount = remainingAmount % 5;
        
        int numberOfPennies = remainingAmount;
        
        cout<<"Your amount        "<< amount <<"         consists of \n ";
/*规范化输出，使计数为0的不显示，计数为1的单位为单数
*/

if(numberOfOneDollars){
                if(numberOfOneDollars==1)
                cout<<"\t"<< numberOfOneDollars <<"        dollar \n" ;
                else
                cout<<"\t"<< numberOfOneDollars <<"        dollars \n" ;
                }
        if(numberOfQuarters)
        {
                if(numberOfQuarters==1)
                cout<<"\t"<< numberOfQuarters << "        quarter \n" ;
                else
                cout<<"\t"<< numberOfQuarters << "        quarters \n" ;
        }
        if(numberOfDimes)        {
                if(numberOfDimes==1)
                cout<<"\t"<< numberOfDimes << "        dime \n" ;
                else
                cout<<"\t"<< numberOfDimes << "        dimes \n" ;
                }
        if(numberOfNickels)
                {
                if(numberOfNickels==1)
                        cout<<"\t"<< numberOfNickels << "        nickel \n" ;
                else
                        cout<<"\t"<< numberOfNickels << "        nickels \n" ;
                }
        if(numberOfPennies)
                {
                if(numberOfPennies==1)        
                        cout<<"\t"<< numberOfPennies << "        pennise";
                else
                        cout<<"\t"<< numberOfPennies << "        pennises";
        }
                return 0[local]1[/local][local]2[/local]
        
        
        
        
}

我用了几组数字（11.56和11.11）进行了测试，其中一组结果不是我预期的效果，后来查看Liang博士的网上习题答案，可悲的是他的程序运行后也有点问题，我比较了下，我们的算法是一样的。
 希望，有做过或者技术娴熟的朋友能来帮忙解答一下。万分感谢

 测试截图 11.11 结果不正确。

我刚刚调试了一下，发现了这个问题上图



11.13测试就正常了，和硬件有关系么？

[ 本帖最后由 p832lun 于 2013-11-17 16:12 编辑 ]

看来这个问题我得问问学电子的人