typedef struct users{
        char name[20];
        int age;
        char f_word[200];
        struct usres *link;
}User;



 #include"include.c"
#include"struct.c"
#include"file.c"
int main(){
        FILE *f;
        User *new = NULL;
        User *start = NULL;
        User *up = NULL;
        char f_name[20];
        int i = 0;
        printf("scanf oprn file name:");
        gets(f_name);
        f = fopen(f_name,"ab+");
        while(!feof(f)){     //这读取会多出一行   知道为什么但是不知道如何解决它
                if(start == NULL){
                        up = start = new = (User *)malloc(sizeof(User));
                }else{
                        new = (User *)malloc(sizeof(User));
                        up->link = new;  //这提示了警告    
                        up = new;
                }
                fread(new,sizeof(User),1,f);
        }
        while(start!=NULL){
                printf("name:%s\t age:%d\t word:%s\n",start->name,start->age,start->f_word);
                start = start->link;      //这提示了警告 
        }
        fclose(f);
}

应该怎么写，自学中   所以会犯很傻逼的问题  求指导

c中貌似没new这关键字吧

feof()暂时不说   这程序new还真不是这个的原因，如果是new的原因应该多行出现警告不止是那两行。

xujia@xujia-Rev-1-0:~/C$ gcc -o ong export.c
export.c: In function ‘main’:
export.c:19:13: warning: assignment from incompatible pointer type [enabled by default]
export.c:26:9: warning: assignment from incompatible pointer type [enabled by default]
xujia@xujia-Rev-1-0:~/C$

出现类型问题。。。

在问问   
将  User *new = NULL;
    User *start = NULL;
    User *up = NULL;
改为
   struct users *new = NULL;
   struct users *start = NULL;
   struct users *up = NULL;
就不会出现警告   

typedef struct users{
        char name[20];
        int age;
        char f_word[200];
        struct usres *link;            //User != struct users   不属于同一个类型?????  需要类型转换？
}User;

求发力

肯定有错啊   你没写include这个文件

自学  自己写的啊