编写一个...输入出生日期（农历、新历都可以）就可以知道活了多少天，多少小时？？大神们求教了.....谢谢你们！！

恩恩.谢谢啦..就是闰年这里有点卡....还有就是农历怎么计算就不知道啦..

#include <stdio.h>
int js(int x,int y,int z)
{
     int i;
     int day0=0;
     int a[12]={31,29,31,30,31,30,31,31,30,31,30,31};
     int b[12]={31,28,31,30,31,30,31,31,30,31,30,31};
     if(z==0)
     {
             for(i=0;i<=y-1;i++)
             day0=day0+a[i];
             return day0+x;
             }
     else
     {
             for(i=0;i<=y-1;i++)
             day0=day0+b[i];
             return day0+x;
             }
    }
int main(void)
{
     int year[2];
     int mon[2];
     int day[2];
     int day0=0;
     int day1,day2;
     int i;
     int z;

     printf("enter your date of birth\n");
     scanf("%d%d%d",&year[0],&mon[0],&day[0]);

     printf("enter the date now\n");
     scanf("%d%d%d",&year[1],&mon[1],&day[1]);
     
     if(i%4==0)  
       {     
            z=0;  
            day1=js(day[0],mon[0],z);
            day0=366-day1;
            }
        else
       {
            z=1;  
            day1=js(day[0],mon[0],z);
            day0=365-day1;
            }
     
     for(i=year[0]+1;i<=year[1];i++)
     {
                                                              
        if(i==year[1])
           {
            if(year[1]%4==0)
            {
              z=0;
              day2=js(day[1],mon[1],z);
              day0=day0+day2;
              break;
                       }
            if(year[1]%4!=0)
            {
              z=1;
              day1=js(day[0],mon[0],z);
              day2=js(day[1],mon[1],z);
              day0=day0+day2;
              break;
                       }
                               }
                     
                     
        if(i%4==0)     
            day0=day0+366;
        else
            day0=day0+365;
                        
                                  }
     printf("%d",day0);
     }
有哪里不对...