#include <stdio.h> #define len sizeof(struct a) #define NULL 0

struct a {char lk; struct a *next ; };

main() {struct a *head,*p,*q,*r; int i; char ch;

head=p=(struct a *) malloc(len);

for(i=1;i<=26;i++) {(p->lk)=('a'+i-1); p->next=(struct a *)malloc(len); p=p->next;

} p->next=NULL; p=head;

while (p->next != NULL)

{ printf("%c ",p->lk); p=p->next; } printf("\n");

printf("input deleted zimu:");

scanf("%c",&ch); p=head; while(ch != '0') { if(head->lk==ch) {head=head->next; free(p); } else

while((p->lk != ch) && (p->next != NULL)) { q=p; p=p->next; }

if(p->lk==ch) {q->next=p->next; free(p);}

printf("\n"); p=head; while(p->next != NULL) {printf("%c ",p->lk); p=p->next; } printf("\n"); printf("input deleted zimu:"); scanf("%c",&ch);

} }

我想实现： 先 打印一行 a,b,c,d,e-----------------------，z LA 然后用 scanf 函数 接受一个字符 ，然后用这个字符 和LA比较，如果一样的话，就删除````

是的``

刚学链表，老师就让做 ，26个字母的插入和删除````

老是让我们做的26个字母的操作我先给大家说一下把`````````````````````````````````````````

首先 在 tc 的输出界面 先打印一行 a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z
                                                         input deleted letter：j

用户输入个 j 后                                a,b,c,d,e,f,g,h,i,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z
                                                           input deleted letter：a

                                                         b,c,d,e,f,g,h,i,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z
                                                         input deleted letter： 输入0后退出界面，回到编程窗口


 

好的，你先去上课````` 我会看别人给我回复地````` 谢谢你了`````哈```````` 链表我用着有点儿迷``````不知道怎么回事，我昨天做了一下午，也没做出来```````` 是不是苯啊`````

#include <stdio.h> #define len sizeof(struct a) #define NULL 0

struct a {char lk; struct a *next ; };

main() {struct a *head,*p,*q; int i; char ch;

head=p=(struct a *) malloc(len);

for(i=1;i<=26;i++) {(p->lk)=('a'+i-1); p->next=(struct a *)malloc(len); p=p->next;

} p->next=NULL;

p=head; while (p->next != NULL)

{ printf("%c ",p->lk); p=p->next; } printf("\n");

p=head; printf("input deleted letter"); scanf("%c",&ch); while(p->lk != ch && p->next != NULL) p=p->next; q=p; p=q->next; free(q); while (p->next != NULL)

{ printf("%c ",p->lk); p=p->next; } printf("\n");

} 大家看看这段程序`````` 我想输入 b后 显示为 a,c,d,e,f,g````````````````z 可是，却是 c,d,e,f,g,h,````````````````z 该怎么改改啊```

我写的程序没头接点``

#include <stdio.h> #define len sizeof(struct a) #include <malloc.h>

struct a {char lk; struct a *next ; };

main() {struct a *head,*p,*q,*s; int i; char ch; head=p=(struct a *) malloc(len); for(i=1;i<=26;i++) { (p->lk)=('a'+i-1); p->next=(struct a *)malloc(len); p=p->next;

} p->next=NULL;

p=head; while (p->next != NULL)

{ printf("%c ",p->lk); p=p->next; } /* printf("\n"); */

q=p=head; printf("\ninput deleted letter:"); scanf("%c",&ch); while(ch != '0') { q=p=head;

while(p->lk != ch && p->next != NULL) {q=p; p=p->next;} if(p==head) { head=head->next;free(p); } else { if(p->lk == ch)

{ q->next=p->next; free(p) ; } else printf("can't find it"); }

q=p=head; printf("\n"); while (p->next != NULL)

{ printf("%c ",p->lk); p=p->next; } /* printf("\n"); */

q=p=head;

printf("\n2:input deleted letter"); fflush(stdin); scanf("%c",&ch); }

p=head; while(p->next != NULL) {printf("%c",p->lk); p=p->next;}

q=p=head; 给修改一下我这蓝字的程序`````````插入的条件错没````？？？ printf("\ninput insert letter"); /*insert */ fflush(stdin); scanf("%c",&ch);

while(ch != '0') { q=p=head; while(p->lk < ch && p->next != NULL) { q=p; p=p->next;}

if(p==head) { s=(struct a *) malloc(len); s->lk=ch; s->next=head; p=s; }

else { if (p->lk == ch) { printf("inserted is exist"); } else {s=(struct a *) malloc(len); s->lk=ch; s->next=p; q->next=s; p=head;}

} printf("\ntest %c\n",p->next->lk);

while(p->next != NULL) {printf("%c",p->lk); p=p->next;} p=head; printf("\n2insert a letter");

fflush(stdin); scanf("%c",&ch);

}

}