Write a program that does the following:

Displays your name on the screen

Calls a function

- to ask for 2 numbers and

- a character input to say whether they want to add or multiply the 2 numbers

- a Switch to determine which function  to execute

                        - do the add

                        Or

                        - do the multiply

Back in main a printf that will show the values of both numbers, the action taken (+ or *) and the result.
不求程序，只求思路。

老师要求要做函数的调用（function），下面是我编写的程序，但是怎么也compile不了，请大侠给我看看，谢谢。
#include<stdio.h>
int add(int, int);
int multiply(int, int);
main()
{
char choice;

printf("A for add\n");
printf("M for multiply\n");
printf("\nPlease input your choice:");
scanf("%c", &choice);

switch (choice)
{
case 'A':
     int a, b, total1;
     printf("Enter the first integer: ");
     scanf("%d", &a);
     printf("Enter the second integer: ");
     scanf("%d", &b);
     total1=add(a, b);
     printf("\nThe total1 is%d", total1);
     break;
case 'M':
     int c, d, total2;
     printf("Enter the first integer: ");
     scanf("%d", &c);
     printf("Enter the second integer: ");
     scanf("%d", &d);
     total2=multiply(c, d);
     printf("\nThe total is%d", total2);
     break;
default: printf("Invalid choice, please try again.\n\n");

}
}
int add(int x, int y)
     {
     int z;
     z=x+y;
     return z;
     }
int multiply(int g, int h)
     {
     int i;
     i=g*h;
     return i;
     }

谢谢楼上的相助。让我烦恼的是，如何让case A break出来就运行
int add(int x, int y)
     {
     int z;
     z=x+y;
     return z;
     }
而case M出来就运行
     int multiply(int g, int h)
     {
     int i;
     i=g*h;
     return i;
     }
呢？

是的。