程序代码：

#include "stdio.h"
#include "stdlib.h"
struct STUDENT
{
    char name[15];
    char number[15];
    int score[5];
};
//输入学生的5门成绩，并输出，学生个数由你输入
int main(int argc, char* argv[])
{
    printf("Hello World!\n");
    int n, i, j;
    struct STUDENT *p;
    printf("Please enter n:");
    scanf("%d", &n);
    p=(struct STUDENT *)malloc(sizeof(struct STUDENT)*n);
    if(p==NULL)
    {
        printf("No enough memory\n");
        exit(0);
    }
    for(i=0; i < n; i++)
    {
        printf("Please enter the student's name:");
        scanf("%s", &(p+i)->name);//问题：为什么用&(p+i)->name和(p+i)->name都正确可以运行？
        //scanf("%s", (p+i)->name);
        printf("Please enter the student's number:");
        scanf("%s", (p+i)->number);//这里不加&；为什么它能运行？
        for(j=0; j < 5; j++)
        {
            printf("Please enter the student's score %d:", j+1);
            scanf("%d", &(p+i)->score[j]);//为什么这里要加&？如果用(p+i)->score[j]程序会错误；
        }
    }
    for(i=0; i < n; i++)
    {
        printf("name:%s\n", (p+i)->name);//问题：为什么这不能加*号？加*号会错误，下面也一样！
        printf("number:%s\n", (p+i)->number);
        printf("maths\tEnglish\tChinese\tphysicial\tchemical\n");
        for(j=0; j < 5; j++)
            printf("%d\t", (p+i)->score[j]);
        printf("\n");
    }
    free(p);
    return 0;
}