Problem Description
Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".
Input
each test case contains two numbers A and B.

Output
for each case, if A is equal to B, you should print "YES", or print "NO".
Sample Input
1 2
2 2
3 3
4 3
Sample Output
NO
YES
YES
NO



我的代码：#include<stdio.h>
#include<string.h>
int main()
{
    char str1[100],str2[100];
    while(scanf("%s%s",str1,str2)!=EOF)
    {
        int len1,len2,i,j;
        len1=strlen(str1);
        len2=strlen(str2);

        for(i=0;i<len1;i++)
        {
            if(str1[i]=='.')
               for(j=len1-1;j>=0;j--)
               {
                if(str1[j]=='0')str1[j]='\0';
                else break;
                }
            }
            if(str1[strlen(str1)-1]=='.')str1[strlen(str1)-1]='\0';

        for(i=0;i<len2;i++)
        {
            if(str2[i]=='.')
                for(j=len2-1;j>=0;j--)
                       {
                           if(str2[j]=='0')str2[j]='\0';
                           else break;
                        }
        }
        if(str2[strlen(str2)-1]=='.')str2[strlen(str2)-1]='\0';

        if(strcmp(str1,str2)==0)printf("YES");
        else printf("NO");
    }
}

有点急啊。。 = = TT 在自己的codeblocks上明明可以的。。