#include<stdio.h>
#include<math.h>
#define maxsize 100
#define eps 0.000001
int main(void)
{
    double a,b,t,x[maxsize],step,s0,s1,f();
    int i,n;

    printf("please input a= and b=\n");
    scanf("%d %d",&a,&b);

    n=1;
    s0=(f(a)+f(b))*(b-a)/2;
    do
    {
            step=(b-a)/n;
        for(i=0;i<n;i++)
        {
        
            x[i]=a+i*step;
            s1=0;
            
                for(i=1;i<=n;i++)
                    s1+=(f(x[i+1])+f(x[i]))*step/2;
                    t=s0;
                    s0=s1;
                    n=n+1;
               
        
        }
        
    }
    while (fabs(s0-t)>eps);
    {
        printf("s0=%lf",s0);
        printf("此时步长为:%d",n);
        printf("\n");
    }
    return 0;
}
double f(double m)
{
    double y;
    y=sqrt(1+pow(m,2));
    return y;
}
   

   

你怎么不帮我分析分析

就像你签名那样，我调试了很久了，做不出来才发帖问的，正是自己想尽了办法再找不出那里错了，才来这里问的，这样才能很快解决自己问题

感谢二楼，但是我已经调试几个小时了，没有错误和警告但是逻辑上错误了，这是我还不能解决的，我想靠大家的帮助从中有所感悟

我编译过了，没有错误，我是学计算机的，谢谢你，按你说的修改了，但是答案没出来

#include<stdio.h>
#include<math.h>
#define maxsize 100
#define eps 0.000001
int main(void)
{
    double a,b,t,x[maxsize],step,s0,s1,f();
    int i,n;

    printf("please input a= and b=\n");
    scanf("%lf  %lf",&a,&b);

    n=1;
    s0=(f(a)+f(b))*(b-a)/2;
    do
    {
            n=n+1;
            step=(b-a)/n;
        for(i=0;i<n;i++)
        {
        
            x[i]=a+i*step;
            s1=0;
                for(i=1;i<=n;i++)
                {
                    s1+=(f(x[i+1])+f(x[i]))*step/2;
                }
                    t=s0;
                    s0=s1;
               
                    
        
        }
        
    }
    while (fabs(s0-t)>eps);
    {
        printf("s0=%lf\n",s0);
        printf("此时步长为:%d",n);
        printf("\n");
    }
    return 0;
}
double f(double m)
{
    double y;
    y=sqrt(1+pow(m,2));
    return y;
}