程序代码：

assume  cs:codesg
codesg  segment

  mov ax,2000h
  mov ss,ax
  mov sp,0h
  add sp,4h
  pop ax
  pop bx

 push ax

 push bx
  pop ax
  pop bx

 

 
  mov ax,4c00h
   int 21h
  codesg ends
  end