题源：http://acm.hdu.

代码如下：
#include<stdio.h>
#include<string.h>
int main()
{
    char ch[10000],a;
    int i=0,k,n,m;
    memset(ch,'0',sizeof(ch));
   
   
    while(scanf("%c",&a)!=-1)
    {
          while(a!='\n')
          {
             ch[i++]=a;
             if(a=='z') k=i-1;
             else if(a=='j') n=i-1;
             scanf("%c",&a);
             }
             m=i-1;
             if((n-k-1==1)&&(k==m-n)) printf("Accepted\n");
            
             else if((n-k-1>=2)&&(m-n>=k)) printf("Accepted\n");
            
             else printf("Wrong Answer\n");
              
             i=0;
            
            
    }
     return 0;
}
谢谢大家先！！