今天做了道题目，是关于复数相加的，我被卡在了实现复数相加后的输出问题上。题目要求输出格式如下：

(1-2i)+(3+4i)=4+2i
(1-2i)+(1+2i)=2
(4)+(-2i)=4-2i
(-1+i)+(1)=i

要分别判断每一个复数的实部和虚部是否为0，为0 的话就不输出。以下是我写的程序，想请大家帮我看下，怎么用比较简便的方法来判断每个复数的实部和虚部是否为0，以便实现正确的输出格式，谢谢！


#include <iostream>
using namespace std;

class Complex
{
   double real,image;
public:
  void set( double a,double b)
  {
   real=a;
   image=b;
  }
  Complex operator +(const Complex &z);  
};
Complex Complex::operator +(const Complex &z)
{
   Complex s;
    s.real=real+z.real;
    s.image=image+z.image;
    if(real==0&&image!=0&&z.real!=0&&z.image!=0&&s.real!=0&&s.image!=0)
    cout<<"("<< noshowpos<<image<<"i"<<")"<<"+"<< noshowpos<<"("<<z.real <<showpos<<z.image<<"i"<<")"<<"="<< noshowpos<<s.real<<showpos<<s.image<<"i"<<endl;
    else if(image==0&&real!=0&&z.real!=0&&z.image!=0&&s.real!=0&&s.image!=0)
    cout<<"("<< noshowpos<<real<<")"<<"+"<< noshowpos<<"("<<z.real <<showpos<<z.image<<"i"<<")"<<"="<< noshowpos<<s.real<<showpos<<s.image<<"i"<<endl;
    else if(z.real==0&&image!=0&&real!=0&&z.image!=0&&s.real!=0&&s.image!=0)
    cout<<"("<< noshowpos<<real<<showpos<<image<<"i"<<")"<<"+"<< noshowpos<<"("<<z.image<<"i"<<")"<<"="<< noshowpos<<s.real<<showpos<<s.image<<"i"<<endl;
    else if(z.image==0&&image!=0&&z.real!=0&&real!=0&&s.real!=0&&s.image!=0)
    cout<<"("<< noshowpos<<real<<showpos<<image<<"i"<<")"<<"+"<< noshowpos<<"("<<z.real<<")"<<"="<< noshowpos<<s.real<<showpos<<s.image<<"i"<<endl;
    else if(s.real==0&&image!=0&&z.real!=0&&z.image!=0&&real!=0&&s.image!=0)
    cout<<"("<< noshowpos<<real<<showpos<<image<<"i"<<")"<<"+"<< noshowpos<<"("<<z.real <<showpos<<z.image<<"i"<<")"<<"="<< noshowpos<<s.image<<"i"<<endl;
    else if(s.image==0&&image!=0&&z.real!=0&&z.image!=0&&s.real!=0&&real!=0)
    cout<<"("<< noshowpos<<real<<showpos<<image<<"i"<<")"<<"+"<< noshowpos<<"("<<z.real <<showpos<<z.image<<"i"<<")"<<"="<< noshowpos<<s.real<<endl;   
    else if(z.real==0&&image==0&&real!=0&&z.image!=0&&s.real!=0&&s.image!=0)
    cout<<"("<< noshowpos<<real<<")"<<"+"<< noshowpos<<"("<<z.image <<")"<<"="<< noshowpos<<s.real <<showpos<<s.image<<"i"<<endl;
    else if(z.image==0&&s.real==0&&image!=0&&z.real!=0&&real!=0&&s.image!=0)
    cout<<"("<< noshowpos<<real<<showpos<<image<<"i"<<")"<<"+"<< noshowpos<<"("<<z.real<<")"<<"="<< noshowpos<<s.image<<"i"<<endl;
    else
    cout<<"("<< noshowpos<<real<<showpos<<image<<"i"<<")"<<"+"<< noshowpos<<"("<<z.real<<showpos<<z.image<<"i"<<")"<<"="<< noshowpos<<s.real <<showpos<<s.image<<"i"<<endl;

   return s;
}
int main()
{        double n,m,n1,m1;
    while(cin>>n>>m>>n1>>m1)
    {
        if(n1==0&&m1==0)
            cout<<"非法输入"<<endl;
        else
        {
         Complex t;
         Complex t1;                                                                                                            
          Complex t2;
         t. set(n,m);
         t1. set(n1,m1);
         t2=t+t1;
        }                        
    }
     return 0;
}

谢谢！