这两天看了指针和结构体之后弄的

求解一下，程序结束时的报错：Run-Time Check Failure #2 Stack around the variable 'list' was corrupted.是指栈被破坏吗，应该如何修改？看名字是list的问题，但我看了半天也找不出哪里的问题，为什么不会影响这个程序的运行，我百度Google了半天没找到。
还有一个：
Run-Time Check Failure #0 - The value of ESP was not properly saved across a function call.  This is usually a result of calling a function declared with one calling convention with a function pointer declared with a different calling convention.

#include <stdio.h>

void input (struct student *,int *);
void output (struct student);
struct student
{
    char name[20];
    int age;
    int score;
    char ach;
    int stdid;
};

int main(void)
{
    struct student list[1];
    int stdidall = 0;

    input(&list[0],&stdidall);
    printf("Complete\n");
    input(&list[1],&stdidall);
    printf("Complete\n");

    printf("--------------------------\n");
    output(list[0]);
    output(list[1]);
    return 0;
}

void input (struct student * temp , int * tempall)
{
    printf("Enter Student Name：");
    scanf("%s",temp->name);
    printf("Enter Student Age：");
    scanf("%d",&temp->age);
    printf("Enter Student Score：");
    scanf("%d",&temp->score);

    if (90 <= temp->score)
        temp->ach = 'A';
    else if (70 <= temp->score)
        temp->ach = 'B';
    else if (60<= temp->score)
        temp->ach = 'C';
    else if (50<= temp->score)
        temp->ach = 'D';
    else
        temp->ach = 'F';
    *tempall = *tempall + 1;
    temp->stdid = *tempall;

    return;
}

void output (struct student temp)
{
    printf("Name：%s\nAge：%d\nScore：%d\nAchievement：%c\nNo.：%d\n", temp.name , temp.age , temp.score , temp.ach , temp.stdid);
    return;
}

这这这.....我.....貌似我一直想着数组从0开始.....

不过这里我定义成1的话不就只有1个元素了吗

那 input(&list[1],&stdidall);又是怎么执行的呢？

感谢！