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标题:谁能让它运行出来?
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xunzeliu
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已结贴  问题点数:20 回复次数:4 
谁能让它运行出来?
程序运用了结构体,好像衔接有错误,结果计算到一半就不进行了,跪求高手解答,有金钱奖励,谢谢!!!
搜索更多相关主题的帖子: 结构体 
2011-05-18 22:08
xunzeliu
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#include "stdio.h"
#include "math.h"
#include "time.h"
#include "stdlib.h"
#define  P  10       //功率
#define  N1  960        //小齿轮转速
#define  I  3.2        //传动比
#define  popsum   10    //定义种群数量
#define  loopmax  500 //定义循环次数
#define  bmgs  16     //定义标准模数
#define  zdcs   36    //定义最大齿数
#define  zxcs   13     //定义最小齿数
#define  zdcx   0.25   //定义最大齿宽系数
#define  zxcx   0.35   //定义最小齿宽系数
#define  PI   3.14     //定义π
#define  R1   0.7        //
#define  R2   0.8
#define  G    0.2        //润滑油粘度
#define  A    0.3        //润滑油的粘压系数
#define  E    3.21        //综合弹性模量
#define  O_F  200        //许用弯曲应力
#define  O_H  150        //许用接触应力
#define  Ka   1          //使用系数
#define  K1   2.39             //计算kv系数
#define  K2   0.0087         
#define  v1    2         //计算Ze参数
#define  v2    3
#define  E1   100.0
#define  E2   100.0
#define  CJ   7         //定义齿轮精度
#define  CP   0.4       //定义交叉概率
#define  MP   0.04     //定义变异概率
#define  x1   100
#define  x2   100
#define  error 0.05
float m[bmgs]={0,2,2.25,2.5,2.75,3,3.5,4,4.5,5,5.5,6,7,8,9,10};
struct geti
{
  int z;               //定义变量小齿轮齿数
  int  mxb;             //定义变量模数的下标
  float ckxs;          //定义变量齿款系数
  float fitness;       //适应度函数值      
}getiold[popsum],      //父代个体组
 getinew[popsum],      //子代个体组   
 getiresult;           //记录最优个体
void chushihua();          //声明初始化函数
void pinggu();             //声明评估函数
void cross();              //声明交叉函数
void bianyi();             //声明变异函数
int  record(int t);
void showresult(int flag);      //声明显示结果函数
int  randsign();
void randtime();
//主函数//
main()                       
{
  int i,t,r,flag;
  randtime();
  chushihua();
  for(i=0;i<=loopmax;i++)
  {
      cross();
      bianyi();
      pinggu();
      printf("%d\n",i);
      record((int) t);
      if((t==1)?1:0) break;  //判断是否终止
  }
  printf("循环次数%d\n",i);
  showresult((int)flag);
}
//初始化函数//
void chushihua()
{   
    int c=0;
    for(c=0;c<popsum;c++)
    {
        getiold[c].z=zxcs+rand()%(zdcs-zxcs);             //随机取13到36之间的整数齿数
        getiold[c].mxb=1+rand()%(bmgs-2);                   //随机取0到7之间的整数
         getiold[c].ckxs=zxcx+(zdcx-zxcx)*rand()/32768.0;     //随机取0.25到0.35之间的小数为齿宽系数
    }
    getiresult.fitness=0;
    for(c=0;c<popsum;c++)
    printf("初始化输出%d,%f,%d\n",getiold[c].z,getiold[c].ckxs,getiold[c].mxb);
}                                                                                          //以上初始化
//评估函数//
void pinggu()
{
    int i,j;
  for(j=1;j<popsum;j++)
   {
      double v,ru,hmin,Wl,Lm,H,J,K,L,Ft,b,T1;  //定义体积,膜厚比,最小油膜厚度,单位接触宽度上的载荷,节锥长,HJKL为计算方便设计,齿轮圆周力,齿宽,小齿轮传递的最大转矩
      double Kv,Kf1,Kf2,Kh1,Kh2,o_f,YsaYfa,o_h,jiao1,aim,cfx1,cfx2;
      double Ze,Zh,f,Ea;
      int Zv;
      aim=v+x1*f+x2*(cfx1+cfx2);   //计算目标函数
      v=PI*(1/I)*((1/I)+1)*m[getinew[j].mxb]*m[getinew[j].mxb]*m[getinew[j].mxb]*getinew[j].z*getinew[j].z+getinew[j].ckxs*(1-getinew[j].ckxs+getinew[j].ckxs/3);     //计算体积
      ru=hmin/sqrt(R1*R1+R2*R2);      //计算膜厚比
      f=1.0/ru;
      hmin=H*J*K*L;                    //计算hmin分解为H,J,K,L四个参数乘积
      H=2.65*pow(A,0.54)/(pow(E,10.03)*pow(Wl,0.13));
      Wl=Ft/b*cos(20*PI/180);           //计算单位接触宽度上的载荷
      Ft=2*T1/((m[getinew[j].mxb])*(1-0.5*(getinew[j].ckxs))*(getinew[j].z));          //计算圆周力
      b=m[getinew[j].mxb]*getinew[j].z*getinew[j].ckxs*sqrt(1/(I*I)+1)/2;              //计算齿宽
      T1=95.5*100000*P/N1;                                           //计算小齿轮的转矩
      J=pow(PI*N1*G/30,0.7);
      K=pow(Lm*sin(20*PI/180),1.13);
      Lm=m[getinew[j].mxb]*getinew[j].z*sqrt(1/(I*I)+1)/2-b;                     //节锥长
      L=pow(I,0.27)/pow((I*I+1),0.43);
      
      //以下判断是否满足约束条件
      o_f=Ka*Kv*Kf1*Kf2*Ft*YsaYfa/(b*m[getinew[j].mxb]*(1-0.5*getinew[j].ckxs));                //计算弯曲应力
      Kv=1+(K1/(Ka*Ft/b)+K2)*getinew[j].z*PI*m[getinew[j].mxb]*getinew[j].z*N1/60/100*sqrt(1/I/I/(1/(I*I)+1));       //动载荷系数
      Kf2=1+(CJ-5)*(Ea-1)/4;                                            //计算齿间载荷分配系数和齿向载荷分布系数(F)
      Kf1=Kf2;
      Ea=1.88-3.2*(1/getinew[j].z+1/(I*getinew[j].z));                        //端面重合度
      Zv=getinew[j].z/cos(jiao1)+1;                                       //当量齿数
      jiao1=atan(I);
      if((Zv>=17)&&(Zv<=23))                                      //计算应力校正系数和齿形系数的乘积
         YsaYfa=8.16-1.276*log((double)Zv);
      else
         YsaYfa=4.85-0.224*log((double)Zv);
      o_h=Ze*Zh*sqrt(4*Ka*Kv*Kh1*Kh2*T1/((getinew[j].ckxs)*(1-0.5*(getinew[j].ckxs))*(1-0.5*(getinew[j].ckxs))*pow((m[getinew[j].mxb])*(getinew[j].z),3)*1/I));
      Ze=sqrt(1.0/(PI*(1-v1*v1)/E1+PI*(1-v2*v2)/E2));
      Zh=2*pow(1/sin(2*20*PI/180),0.5);  //   
      Kh1=1.0;                             //计算齿间载荷分配系数和齿向载荷分布系数(H)
      Kh2=1.0;
      if(o_f<=O_F)
         cfx1=0;
      else
         cfx1=o_f-O_F;
      if(o_h<=O_H)
         cfx2=0;
      else
         cfx2=o_h-O_H;
      getinew[j].fitness=10000*1.0/aim;
      if(getinew[j].fitness>getinew[1].fitness)
           getinew[1].fitness=getinew[j].fitness;
           getinew[1].z=getinew[j].z;
           getinew[1].mxb=getinew[j].mxb;
           getinew[1].ckxs=getinew[j].ckxs;
  }
  getinew[0].fitness=getinew[1].fitness;
 printf("%d,%f,%f\n",getinew[1].z,getinew[1].ckxs,getinew[0].fitness);
}
//交叉函数//
void cross()
{
  int i,j,k;
  int  a[popsum];
  for(i=0;i<popsum;i++)
      a[i]=0;
      k=1;
   for(i=0;i<popsum;i++)
   {
     if(a[i]==0)
     {     do
         j=i+1+rand()%(popsum-1);
         while(a[j]!=0);
       if(randsign(CP)==1)
       {
          float x;
          x=rand(0,1)/100.0;
          getinew[k].z=x*getiold[i].z+(1-x)*getiold[j].z;
          getinew[k+1].z=(1-x)*getiold[i].z+x*getiold[j].z;
          getinew[k].mxb=x*getiold[i].mxb+(1-x)*getiold[j].mxb;
          getinew[k+1].mxb=(1-x)*getiold[i].mxb+x*getiold[j].mxb;
          getinew[k].ckxs=x*getiold[i].ckxs+(1-x)*getiold[j].ckxs;
          getinew[k+1].ckxs=(1-x)*getiold[i].ckxs+x*getiold[j].ckxs;
          k=k+2;
       }
       else
       {
          getinew[k].z=getiold[i].z;
          getinew[k+1].z=getiold[j].z;
          getinew[k].mxb=getiold[i].mxb;
          getinew[k+1].mxb=getiold[j].mxb;
          getinew[k].ckxs=getiold[i].ckxs;
          getinew[k+1].ckxs=getiold[j].ckxs;
          k=k+2;
       }
       a[i]=a[j]=1;
     }
 printf("交叉输出%d,%d,%f\n",getinew[i].z,getinew[i].mxb,getinew[i].ckxs);
  }
     for(i=0;i<popsum;i++)
         a[i]=0;
}
//变异函数
void bianyi()
{
     int i,j,k,l,t;
     float cmp;
     cmp=1-pow(1-MP,3);
     for(i=0;i<popsum;i++)
     {
         if(randsign(cmp)==1)
         {
             j=0+rand()%popsum;
             k=0+rand()%2;
             if(k=0)
                  getinew[j].z=+(rand()%(zdcs-getinew[j].z));
             else
                 if(k=1)
                 getinew[j].mxb=+rand()%(bmgs-getinew[j].mxb);
             else
                 getinew[j].ckxs=+((zdcx-getinew[j].ckxs)*rand()/32768.0);
         }
     }
 }
 int record(int t)
 {   int flag=0;
     float x=getinew[0].fitness-getiresult.fitness;
     printf("%f\n",x);
     if(abs(x)<error)
     {
         flag++;
             return 1;
     }
     else
         flag=0;
         getiresult.fitness=getinew[0].fitness;
     return 0;
 }
 //显示结果函数
void showresult(int flag)
 {
    int i,j;
    if(flag==0)
      printf("已到最大搜索次数,搜索失败!");
    else
      getiresult.z=getinew[1].z;
      getiresult.mxb=getinew[1].mxb;
      getiresult.ckxs=getinew[1].ckxs;
      getiresult.fitness=getinew[1].fitness;
      printf("最优齿数为%d\n",getiresult.z);
      printf("最优模数为%f\n",m[getinew[j].mxb]);
      printf("最优齿宽系数为%f\n",getiresult.ckxs);
      printf("最优适应度函数值为%f\n",getiresult.fitness);
 }
 int randsign(float p)
 {
  if(rand()>(p*32768))
        return 0;
  else return 1;
 }
 void randtime()
 {
     int time1;
     long time2;
     time2=time(NULL);
     time1=(unsigned) time2/2;
     srand(time1);
 }



























 






   







2011-05-18 22:10
xunzeliu
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回复 3楼 刹那间的回忆
你很牛啊,一眼就看出问题了,关键在于函数交叉和变异后理论上那个不为0,但是运行后就为零了,导致终止,但是怎么判断,老师说我交叉和变异函数有问题,他看了看没错误,另外我还有问题向你求教!!
2011-05-19 14:25
xunzeliu
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回复 5楼 xunzeliu
Loaded 'ntdll.dll', no matching symbolic information found.
Loaded 'C:\Windows\System32\kernel32.dll', no matching symbolic information found.
Loaded 'C:\Windows\System32\KernelBase.dll', no matching symbolic information found.
First-chance exception in lb.exe: 0xC0000005: Access Violation.
First-chance exception in lb.exe: 0xC0000005: Access Violation.
First-chance exception in lb.exe: 0xC0000005: Access Violation.



遇到这种问题怎么办?
2011-05-19 14:28
xunzeliu
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回复 3楼 刹那间的回忆
我现在程序又改了改,大侠再帮忙看看!!
#include "stdio.h"
#include "math.h"
#include "time.h"
#include "stdlib.h"
#define  P  10          //功率
#define  N1  960        //小齿轮转速
#define  I  3.2         //传动比
#define  popsum   1000   //定义种群数量
#define  loopmax  50   //定义循环次数
#define  bmgs  15       //定义标准模数
#define  zdcs   36      //定义最大齿数
#define  zxcs   13      //定义最小齿数
#define  zdcx   0.25    //定义最大齿宽系数
#define  zxcx   0.35    //定义最小齿宽系数
#define  PI   3.14       //定义π
#define  R1   0.7        //
#define  R2   0.8
#define  G    0.2        //润滑油粘度
#define  A    0.3        //润滑油的粘压系数
#define  E    3.21        //综合弹性模量
#define  O_F  200000000        //许用弯曲应力
#define  O_H  150000000        //许用接触应力
#define  Ka   1          //使用系数
#define  K1   2.39             //计算kv系数
#define  K2   0.0087         
#define  v1    2         //计算Ze参数
#define  v2    3
#define  E1   100.0
#define  E2   100.0
#define  CJ   7         //定义齿轮精度
#define  CP   0.4       //定义交叉概率
#define  MP   0.04     //定义变异概率
#define  x1   10
#define  x2   10
#define  error 0.05
float m[bmgs+1]={0,2,2.25,2.5,2.75,3,3.5,4,4.5,5,5.5,6,7,8,9,10};
struct geti
{
  int z;               //定义变量小齿轮齿数
  int  mxb;             //定义变量模数的下标
  float ckxs;          //定义变量齿款系数
  float fitness;       //适应度函数值      
}getiold[popsum+1],      //父代个体组
 getinew[popsum+1],      //子代个体组   
 getiresult;           //记录最优个体
void chushihua();          //声明初始化函数
void pinggu();             //声明评估函数
void cross();              //声明交叉函数
void bianyi();             //声明变异函数
int  record(int t);
void showresult(int flag);      //声明显示结果函数
int  randsign();
void randtime();
//主函数//
main()                       
{
  int i,t,r,flag;
  randtime();
  chushihua();
  for(i=0;i<loopmax;i++)
  {
      cross();
      bianyi();
      pinggu();
怎么让它运行完这步没有成为0的结构体成员!!!
      record((int) t);
      if((t==1)?1:0) break;  //判断是否终止
  }
  printf("循环次数%d\n",i);
  //showresult((int)flag);
}
//初始化函数//
void chushihua()
{   
    int c;
    for(c=1;c<=popsum;c++)
    {
        getiold[c].z=zxcs+rand()%(zdcs-zxcs);             //随机取13到36之间的整数齿数
        getiold[c].mxb=1+rand()%(bmgs-1);                   //随机取0到7之间的整数
         getiold[c].ckxs=zxcx+(zdcx-zxcx)*rand()/32768.0;     //随机取0.25到0.35之间的小数为齿宽系数
    }
    getiresult.fitness=0;
    for(c=1;c<=popsum;c++)
    printf("初始化输出%d,%f,%d,%d\n",getiold[c].z,getiold[c].ckxs,getiold[c].mxb,c);
}                                                                                          //以上初始化
//评估函数//
void pinggu()
{
   int i,j;
   for(j=1;j<=popsum;j++)
   {
      double v,ru,hmin,Wl,Lm,H,J,K,L,Ft,b,T1;  //定义体积,膜厚比,最小油膜厚度,单位接触宽度上的载荷,节锥长,HJKL为计算方便设计,齿轮圆周力,齿宽,小齿轮传递的最大转矩
      double Kv,Kf1,Kf2,Kh1,Kh2,o_f,YsaYfa,o_h,jiao1,aim,cfx1,cfx2;
      double Ze,Zh,f,Ea;
      int Zv;
      aim=v+x1*f+x2*(cfx1+cfx2);   //计算目标函数
      v=PI*(1/I)*((1/I)+1)*m[getinew[j].mxb]*m[getinew[j].mxb]*m[getinew[j].mxb]*getinew[j].z*getinew[j].z+getinew[j].ckxs*(1-getinew[j].ckxs+getinew[j].ckxs/3);     //计算体积
      ru=hmin/sqrt(R1*R1+R2*R2);      //计算膜厚比
      f=1.0/ru;
      printf("目标%f",aim);
      hmin=H*J*K*L;                    //计算hmin分解为H,J,K,L四个参数乘积
      H=2.65*pow(A,0.54)/(pow(E,10.03)*pow(Wl,0.13));
      Wl=Ft/b*cos(20*PI/180);           //计算单位接触宽度上的载荷
      Ft=2*T1/((m[getinew[j].mxb])*(1-0.5*(getinew[j].ckxs))*(getinew[j].z));          //计算圆周力
      b=m[getinew[j].mxb]*getinew[j].z*getinew[j].ckxs*sqrt(1/(I*I)+1)/2;              //计算齿宽
      T1=95.5*100000*P/N1;                                           //计算小齿轮的转矩
      J=pow(PI*N1*G/30,0.7);
      K=pow(Lm*sin(20*PI/180),1.13);
      Lm=m[getinew[j].mxb]*getinew[j].z*sqrt(1/(I*I)+1)/2-b;                     //节锥长
      L=pow(I,0.27)/pow((I*I+1),0.43);
      
      //以下判断是否满足约束条件
      o_f=Ka*Kv*Kf1*Kf2*Ft*YsaYfa/(b*m[getinew[j].mxb]*(1-0.5*getinew[j].ckxs));                //计算弯曲应力
      Kv=1+(K1/(Ka*Ft/b)+K2)*getinew[j].z*PI*m[getinew[j].mxb]*getinew[j].z*N1/60/100*sqrt(1/I/I/(1/(I*I)+1));       //动载荷系数
      Kf2=1+(CJ-5)*(Ea-1)/4;                                            //计算齿间载荷分配系数和齿向载荷分布系数(F)
      Kf1=Kf2;
      Ea=1.88-3.2*(1/getinew[j].z+1/(I*getinew[j].z)); 前面结构体成员不为零,这就没错啦!!                       //端面重合度
      Zv=getinew[j].z/cos(jiao1)+1;                                       //当量齿数
      jiao1=atan(I);
      if((Zv>=17)&&(Zv<=23))                                      //计算应力校正系数和齿形系数的乘积
         YsaYfa=8.16-1.276*log((double)Zv);
      else
         YsaYfa=4.85-0.224*log((double)Zv);
      o_h=Ze*Zh*sqrt(4*Ka*Kv*Kh1*Kh2*T1/((getinew[j].ckxs)*(1-0.5*(getinew[j].ckxs))*(1-0.5*(getinew[j].ckxs))*pow((m[getinew[j].mxb])*(getinew[j].z),3)*1/I));
      Ze=sqrt(1.0/(PI*(1-v1*v1)/E1+PI*(1-v2*v2)/E2));
      Zh=2*pow(1/sin(2*20*PI/180),0.5);    //   
      Kh1=1.0;                             //计算齿间载荷分配系数和齿向载荷分布系数(H)
      Kh2=1.0;
      if(o_f<=O_F)
         cfx1=0;
      else
         cfx1=o_f-O_F;
      if(o_h<=O_H)
         cfx2=0;
      else
         cfx2=o_h-O_H;
      getinew[j].fitness=10000000000*1.0/aim;
      printf("适应度%f\n",getinew[j].fitness);
      if(getinew[j].fitness>getinew[0].fitness)
           getinew[0].fitness=getinew[j].fitness;
           getinew[0].z=getinew[j].z;
           getinew[0].mxb=getinew[j].mxb;
           getinew[0].ckxs=getinew[j].ckxs;
  }
// printf("循环最优%d,%f,%f,%f\n",getinew[0].z,m[getinew[0].mxb],getinew[0].ckxs,getinew[0]);
}
//交叉函数//
void cross()
{
  int i,j,k;
  int  a[popsum+1];
  for(i=1;i<=popsum;i++)
      a[i]=0;
      k=1;
   for(i=1;i<=popsum;i++)
   {
     if(a[i]==0)
     {     do
         j=i+1+rand()%(popsum-1);
         while(a[j]!=0);
       if(randsign(CP)==1)
       {
          float x;
          x=rand(0,1)/100.0;
          getinew[k].z=(int)x*getiold[i].z+(1-x)*getiold[j].z+0.5;
          getinew[k+1].z=(int)(1-x)*getiold[i].z+x*getiold[j].z+0.5;
          getinew[k].mxb=(int)x*getiold[i].mxb+(1-x)*getiold[j].mxb+0.5;
          getinew[k+1].mxb=(int)(1-x)*getiold[i].mxb+x*getiold[j].mxb+0.5;
          getinew[k].ckxs=x*getiold[i].ckxs+(1-x)*getiold[j].ckxs;
          getinew[k+1].ckxs=(1-x)*getiold[i].ckxs+x*getiold[j].ckxs;
          k=k+2;
       }
       else
       {
          getinew[k].z=getiold[i].z;
          getinew[k+1].z=getiold[j].z;
          getinew[k].mxb=getiold[i].mxb;
          getinew[k+1].mxb=getiold[j].mxb;
          getinew[k].ckxs=getiold[i].ckxs;
          getinew[k+1].ckxs=getiold[j].ckxs;
          k=k+2;
       }
       a[i]=a[j]=1;说这有问题!!
     }
 printf("交叉输出%d,%d,%f\n",getinew[i].z,getinew[i].mxb,getinew[i].ckxs);
  }
     for(i=1;i<=popsum;i++)
         a[i]=0;
}
//变异函数
void bianyi()
{
     int i,j,k,l,t;
     float cmp;
     cmp=1-pow(1-MP,3);
     for(i=0;i<=popsum;i++)
     {
         if(randsign(cmp)==1)
         {
             j=1+rand()%popsum;
             k=0+rand()%2;
             if(k=0)
                  getinew[j].z=+(rand()%(zdcs-getinew[j].z));
             else
                 if(k=1)
                 getinew[j].mxb=+rand()%(bmgs-getinew[j].mxb);
             else
                 getinew[j].ckxs=+((zdcx-getinew[j].ckxs)*rand()/32768.0);
         }
         else
         {   
             j=1+rand()%popsum;
             k=0+rand()%2;
             if(k=0)
                 getinew[j].z=-(rand()%(getinew[j].z-zxcs));
             else
                 if(k=1)
                     getinew[j].mxb=-(rand()%getinew[j].mxb-1);
             else
                 getinew[j].ckxs=-((getinew[j].ckxs-zxcx)*rand()/32768.0);
         }


 printf("变异输出%d,%d,%f\n",getinew[i].z,getinew[i].mxb,getinew[i].ckxs);
     }
 }
 int record(int t)
 {   int flag=0;
     float x=getinew[0].fitness-getiresult.fitness;
     printf("误差%f\n",x);
     if(abs(x)<error)
     {
         flag++;
             return 1;
     }
     else
         flag=0;
         getiresult.fitness=getinew[0].fitness;
     return 0;
printf("总最优%f\n",getiresult.fitness);
 }
 //显示结果函数
void showresult(int flag)
 {
    int i,j;
    if(flag==0)
      printf("已到最大搜索次数,搜索失败!");
    else
      getiresult.z=getinew[1].z;
      getiresult.mxb=getinew[1].mxb;
      getiresult.ckxs=getinew[1].ckxs;
      getiresult.fitness=getinew[1].fitness;
      printf("最优齿数为%d\n",getiresult.z);
      printf("最优模数为%f\n",m[getinew[j].mxb]);
      printf("最优齿宽系数为%f\n",getiresult.ckxs);
      printf("最优适应度函数值为%f\n",getiresult.fitness);输出函数不会编,帮忙编下
 }
 int randsign(float p)
 {
  if(rand()>(p*32768))
        return 0;
  else return 1;
 }
 void randtime()
 {
     int time1;
     long time2;
     time2=time(NULL);
     time1=(unsigned) time2/2;
     srand(time1);
 }



























 






   









[ 本帖最后由 xunzeliu 于 2011-5-19 14:40 编辑 ]
2011-05-19 14:36
快速回复:谁能让它运行出来?
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