求空格，大写，小写，数字各有几个
#include<stdio.h>
#include<stdlib.h>
#define N 100
void main()
{
    char*p=(char*)malloc(N*sizeof(char));
    int num=0,space=0,up=0,low=0,other=0;
    printf("input the string:");
    gets(p);
    for(;*p!='\0';p++)
    {
        if((*p>='0')&&(*p<='9'))
            num++;
        else if(*p==' ')
            space++;
        else if((*p>='A')&&(*p<='Z'))
            up++;
        else if((*p>='a')&&(*p<='z'))
            low++;
        else
            other++;
    }
    printf("num=%d,space=%d,up=%d,low=%d,other=%d\n",num,space,up,low,other);
}
为什么char*p...不能换成p[N];
#include<stdio.h>
#include<stdlib.h>
#define N 100
void main()
{
    char p[N];
    int num=0,space=0,up=0,low=0,other=0;
    printf("input the string:");
    gets(p);
    for(;*p!='\0';p++)
    {
        if((*p>='0')&&(*p<='9'))
            num++;
        else if(*p==' ')
            space++;
        else if((*p>='A')&&(*p<='Z'))
            up++;
        else if((*p>='a')&&(*p<='z'))
            low++;
        else
            other++;
    }
    printf("num=%d,space=%d,up=%d,low=%d,other=%d\n",num,space,up,low,other);
}
错误： error C2105: '++' needs l-value

不是很正确，刚刚在书里找到了，p是地址常量（地址即指针），所以p++无法实现

[ 本帖最后由 kechujian 于 2011-4-7 21:32 编辑 ]