why divide overflow
程序代码:
data segment num dw 543 data ends code segment assume cs:code,ds:data start: mov ax,data mov ds,ax mov cx,10 mov ax,num mov bh,0 again: div cx mov bl,al push bx mov al,0 cmp al,0 jz exit jmp again exit: pop bx mov dx,bx mov ah,02h int 21h mov ah,4ch int 21h code ends end start问题如上希望高手解答下,呵呵