下面是求2或3阶的行列式的程序，但是输入2或3就输出your number is too large.
指教请


#include "stdio.h"
void main()
{
    float a,b,c,d,e,f,g,h,i,n,z;
    printf("please type the amount of hls.\n");
    scanf("%d",&n);
    if (n==1)
    {
        printf("your number is wrong,please type again.\n");
    }
    else
    {
        if (n==2)
        {
            printf("please type the 4 number of the hls.\n");
            scanf("%f,%f,%f,%f",&a,&b,&c,&d);
            z=a*c-b*d;
            printf("the result is %f,\n",z);
        }
        else
        {
            if (n==3)
            {
                printf("please type the 4 number of the hls.\n");
                scanf("%f,%f,%f,%f,%f,%f,%f,%f,%f",&a,&b,&c,&d,&e,&f,&g,&h,&i);
                n=a*e*i-a*f*h+a*d*i-b*g*f+c*d*h-c*g*e;
                printf("the result is %f,\n",z);
            }
            else
            {
                printf("your number is too large.\n");
            }
        }
    }
}




可以了，谢谢三楼的

[ 本帖最后由 chenwei435 于 2011-2-22 19:12 编辑 ]

呵呵，这一句也错了n=a*e*i-a*f*h+a*d*i-b*g*f+c*d*h-c*g*e;
应该是z=a*e*i-a*f*h+a*d*i-b*g*f+c*d*h-c*g*e;
刚才测试时发现的