编写一个程序，要求用户输入一个两位数，然后显示该数的英文单词：

Enter a two-digit number: 45
You entered the number forty-five.

提示：把数分解为两个数字。用一个switch语句显示第一位数字对应的单词（“twenty”、“thirty”等），
用第二个switch语句显示第二位数字对应的单词。不要忘记11-19需要特殊处理。

# include <stdio.h>
# include <stdlib.h>
int main (void)
{
    int x,y,n;
    printf ("Enter a two-digit number:");
    scanf ("%d%d\n",&x,&y);
    printf("You entered the nember ");
    switch (x) {
           case 2:  printf("twenty");    break;      
           case 3:  printf("thirty");    break;         
           case 4:  printf("forty");     break;        
           case 5:  printf("fifty");     break;      
           case 6:  printf("sixty");     break;   
           case 7:  printf("seventy");   break;   
           case 8:  printf("eighty");    break;     
           case 9:  printf("ninety");    break;     
           }
    switch (y) {
           case 0:  printf("zero");      break;      
           case 1:  printf("one");       break;   
           case 2:  printf("two");       break;   
           case 3:  printf("three");     break;         
           case 4:  printf("four");      break;
           case 5:  printf("five");      break;
           case 6:  printf("six");       break;
           case 7:  printf("seven");     break;
           case 8:  printf("eight");     break;
           case 9:  printf("nine");      break;
           }                  
           
    system ("pause");
    return 0;
}

请问我编写的哪里错了，还有11到19应该怎么写呢？

调试时只是出现：

Enter a two-digit number
  
这一行

为什么要用 字符类型 char ？
用整形 int 为何不可呢？

int m=x-'0';
    int n=y-'0';
    int s=10*m+n;

还想请问：以上用
int s=10*x+y;

可以吗？不定义 m,n 了。
谢谢~

哦，有点明白~

如果还是定义 x，y 整形，然后把scanf ("%d%d",&x,&y);  改为 scanf ("%1d%1d",&x,&y);
这样可以把两位数独立了吧？

然后我这样编了下面：

# include <stdio.h>
# include <stdlib.h>
int main (void)
{
    int x,y,n;
    n=10*x+y;
    printf ("Enter a two-digit number:");
    scanf ("%1d%1d",&x,&y);
    printf("You entered the nember ");
            
  if (n>=20)
   {
    switch (x) {
           case 2:  printf("twenty-");    break;      
           case 3:  printf("thirty-");    break;         
           case 4:  printf("forty-");     break;        
           case 5:  printf("fifty-");     break;      
           case 6:  printf("sixty-");     break;   
           case 7:  printf("seventy-");   break;   
           case 8:  printf("eighty-");    break;     
           case 9:  printf("ninety-");    break;     
           }
    switch (y) {
           case 0:  printf("");           break;      
           case 1:  printf("one");        break;   
           case 2:  printf("two");        break;   
           case 3:  printf("three");      break;         
           case 4:  printf("four");       break;
           case 5:  printf("five");       break;
           case 6:  printf("six");        break;
           case 7:  printf("seven");      break;
           case 8:  printf("eight");      break;
           case 9:  printf("nine");       break;
           }  
    }
  else
    {
    switch (n) {
           case 10: printf("ten");        break;     
           case 11: printf("eleven");     break;
           case 12: printf("twelve");     break;
           case 13: printf("thirteen");   break;
           case 14: printf("fourteen");   break;
           case 15: printf("fifteen");    break;
           case 16: printf("sixteen");    break;
           case 17: printf("seventeen");  break;
           case 18: printf("eighteen");   break;
           case 19: printf("nineteen");   break;
           }
    }                        
    system ("pause");
    return 0;
}

可是红色部分好像没有作用，我输入 10 的时候，显示的是“”（也就是空格）


又是哪里错了呢？

嗯嗯，明白
请你看一下如果 要输出 00到 09 就又不对了
# include <stdio.h>
# include <stdlib.h>
int main (void)
{
    int x,y,n;
   
    printf ("Enter a two-digit number:");
    scanf ("%1d%1d",&x,&y);
    printf("You entered the nember ");
    n=10*x+y;
     
     
  if (n>=20)
   {
    switch (x) {
           case 2:  printf("twenty-");    break;      
           case 3:  printf("thirty-");    break;         
           case 4:  printf("forty-");     break;        
           case 5:  printf("fifty-");     break;      
           case 6:  printf("sixty-");     break;   
           case 7:  printf("seventy-");   break;   
           case 8:  printf("eighty-");    break;     
           case 9:  printf("ninety-");    break;     
           }
    switch (y) {
           case 0:  printf("");           break;      
           case 1:  printf("one");        break;   
           case 2:  printf("two");        break;   
           case 3:  printf("three");      break;         
           case 4:  printf("four");       break;
           case 5:  printf("five");       break;
           case 6:  printf("six");        break;
           case 7:  printf("seven");      break;
           case 8:  printf("eight");      break;
           case 9:  printf("nine");       break;
           }  
    }
  else
    {
    switch (n) {
           case 00: printf("zero");       break;
           case 01: printf("one");        break;
           case 02: printf("two");        break;
           case 03: printf("three");      break;
           case 04: printf("four");       break;
           case 05: printf("five");       break;
           case 06: printf("six");        break;
           case 07: printf("seven");      break;
           case 08: printf("eight");      break;      //这行调试时出错
           case 09: printf("nine");       break;      //这行调试时出错   
           case 10: printf("ten");        break;     
           case 11: printf("eleven");     break;
           case 12: printf("twelve");     break;
           case 13: printf("thirteen");   break;
           case 14: printf("fourteen");   break;
           case 15: printf("fifteen");    break;
           case 16: printf("sixteen");    break;
           case 17: printf("seventeen");  break;
           case 18: printf("eighteen");   break;
           case 19: printf("nineteen");   break;
           }
    }
           
           
  
    system ("pause");
    return 0;
}


红色是我增加的部分，可是最后两行，08，09 有错
可是前面几行都没错，我就不明白了~~请教一下~
真的不好意思麻烦你，谢谢啦~

噢噢。我终于明白了，应该没有问题了
非常感谢！~