给一个不多于5位的正整数，要求：
1.求出它是几位数；
2.安逆序输出。
#include <stdio.h>
void main()
{
    int z;
long int a,gw,sw,bw,qw,ww;
printf("输入99999以内的数");
scanf("%ld",&a);
if(a>9999){z=5;ww=a/10000;}
else if(a>999){z=4;qw=a/1000;}
else if(a>99){z=3;bw=a/100;}
else if(a>9){z=2;sw=a/10;}
else z=1;gw=a/1;
printf("是%d位数\n",z);
printf("逆序是");
            if(z==5)
            printf("%ld%ld%ld%ld%ld\n",gw,sw,bw,qw,ww);
            else if(z==4)
            printf("%ld%ld%ld%ld\n",gw,sw,bw,qw);
            else if(z==3)
            printf("%ld%ld%ld\n",gw,sw,bw);
            else if(z==2)
            printf("%ld%ld\n",gw,sw);
            else printf("%ld\n",gw);
}

原来是这样的 谢谢你了
#include <stdio.h>
void main()
{
    int z;
long int a,gw,sw,bw,qw,ww;
printf("输入99999以内的数");
scanf("%ld",&a);
if(a>9999)z=5;
else if(a>999)z=4;
else if(a>99)z=3;
else if(a>9)z=2;
else z=1;
printf("是%d位数\n",z);
ww=a/10000;
qw=(a-ww*10000)/1000;
bw=(a-ww*10000-qw*1000)/100;
sw=(a-ww*10000-qw*1000-bw*100)/10;
gw=(a-ww*10000-qw*1000-bw*100-sw*10);
printf("逆序是");
            if(z==5)
            printf("%ld%ld%ld%ld%ld\n",gw,sw,bw,qw,ww);
            else if(z==4)
            printf("%ld%ld%ld%ld\n",gw,sw,bw,qw);
            else if(z==3)
            printf("%ld%ld%ld\n",gw,sw,bw);
            else if(z==2)
            printf("%ld%ld\n",gw,sw);
            else printf("%ld\n",gw);
}