//问题：
//假设有火车票100张，创建10个线程模拟10个售票点，每个售票点500毫秒买一张票。打印出售票过程，注意使用synchronized确保同一张票只能卖出一次。

class TicketsSell implements Runnable {
         
   
         static int tickets=1;//实例化票数
    int num;

    public TicketsSell(int num) {//  构造方法
        this.num = num;
    }

    public  synchronized void run() {
      //synchronized(this){// 同步该方法
        for (int i=0; i< 100; i++) {
               

           if(tickets<100) {
            try {
                Thread.sleep(500);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
            System.out.println("第" + num + "售票点卖出第" + (tickets++) + "张票");
   
            }
            
           }
           
      
    }
}

public class Station {

    public static void main(String[] args) {
        
       Thread wicket1 = new Thread(new TicketsSell(1));
        Thread wicket2 = new Thread(new TicketsSell(2));
        Thread wicket3 = new Thread(new TicketsSell(3));
        Thread wicket4 = new Thread(new TicketsSell(4));
        Thread wicket5 = new Thread(new TicketsSell(5));
        Thread wicket6 = new Thread(new TicketsSell(6));
        Thread wicket7 = new Thread(new TicketsSell(7));
        Thread wicket8 = new Thread(new TicketsSell(8));
        Thread wicket9 = new Thread(new TicketsSell(9));
        Thread wicket10 = new Thread(new TicketsSell(10));
        wicket1.start();
        wicket2.start();
        wicket3.start();
        wicket4.start();
        wicket5.start();
        wicket6.start();
        wicket7.start();
        wicket8.start();
        wicket9.start();
        wicket10.start();
      
    }

}
运行结果： 为什么会超出100张！ 我找不出错误，知道的说下！