#include<stdio.h>
#include<string.h>
void main()
{
    char digit[][3]={"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
    char place[][3]={"","拾","佰","仟","万","亿","角","分"};
    char sum_mon[44][3];/*定义存放大写钱数的二维数组*/
    int num[20],s;
    int  i,j,k,m,flag=1,len,sum;
    double money,dec_mon;
    unsigned long int_mon;
    printf("input money(0~4294967295.99):\n");
    scanf("%lf",&money);
    int_mon=(unsigned long)money;
    dec_mon=money-(double)int_mon;
    for(i=1;i<=20;i++)
    {
            num[i-1]=int_mon%10;
            int_mon=int_mon/10;
    }
       for(j=0,i=19;i>=j;i--)
    {
        if((num[i]!=0)&&(flag==1))
        {
            flag=0;
            sum=i+1;/*整数部分位数*/
            }
        if(flag==0)
        {
            s=num[i];
            num[i]=num[j];
            num[j]=s;
            j++;
            }
    }                     /*整数部分转换为字符数组*/
    switch(sum/4)
    {   
        case 0:k=sum%4;
               for(i=num[0],j=0,s=0,m=k-1;j<k;j++,m--,i=num[j])
               {
                    strcpy(sum_mon[s],digit[i]);/*把相应位的大写给sum_mon[][3]*/
                    strcpy(sum_mon[s+1],place[m]);/*在相应位大写后面加上位名*/
                    s=s+2;                  
               }              /*输入的整数部分位小于4*/
               strcpy(sum_mon[s-1],"元");
               break;
       case 1:k=sum%4;
              for(i=num[0],j=0,s=0,m=k-1;j<k;j++,m--,i=num[j])
               {
                    strcpy(sum_mon[s],digit[i]);
                    strcpy(sum_mon[s+1],place[m]);
                    s=s+2;                  
                    }
              if(k!=0)
                  strcpy(sum_mon[s-1],place[4]);/*把万给二维数组*/
              strcpy(sum_mon[s],digit[num[k]]);   
              strcpy(sum_mon[s+1],place[3]);/*把千位数和仟给数组*/
              for(i=num[k+1],j=0,s=s+2,m=2;j<3;j++,m--,i=num[j+k+1])
              {         
                    strcpy(sum_mon[s],digit[i]);     
                    strcpy(sum_mon[s+1],place[m]);
                    s=s+2;                       
                    }   
              strcpy(sum_mon[s-1],"元");
              break;   /*输入的整数部分位数小于8*/     
       case 2:k=sum%4;
              for(i=num[0],j=0,s=0,m=k-1;j<k;j++,m--,i=num[j])
               {
                    strcpy(sum_mon[s],digit[i]);
                    strcpy(sum_mon[s+1],place[m]);
                    s=s+2;                  
                    }
              if(k!=0)
                  strcpy(sum_mon[s-1],place[5]);/*把亿给二维数组*/
              strcpy(sum_mon[s],digit[num[k]]);   
              strcpy(sum_mon[s+1],place[3]);
              for(i=num[k+1],j=0,s=s+2,m=2;j<3;j++,m--,i=num[j+k+1])
              {
                    strcpy(sum_mon[s],digit[i]);
                    strcpy(sum_mon[s+1],place[m]);
                    s=s+2;                  
                    }
              strcpy(sum_mon[s-1],place[4]);
              strcpy(sum_mon[s],digit[num[k+4]]);   
              strcpy(sum_mon[s+1],place[3]);
              for(i=num[k+1+4],j=0,s=s+2,m=2;j<3;j++,m--,i=num[j+k+1+4])
              {         
                    strcpy(sum_mon[s],digit[i]);     
                    strcpy(sum_mon[s+1],place[m]);
                    s=s+2;                       
                    }   
              strcpy(sum_mon[s-1],"元");
              break;/*输入的整数部分位数小于12*/
    }
    len=2*sum;   
    for(k=0,i=0,j=0;i<2;i++,j=j+2)
    {
        dec_mon=dec_mon*10;
        k=((int)dec_mon)%10;
        strcpy(sum_mon[len+j],digit[k]);
        strcpy(sum_mon[len+j+1],place[i+6]);
    }/*小数部分*/
   for(i=0;i<len+4;i++)
        printf("%s",sum_mon[i]);/*输出大写字符*/
   getch();
}


那位高手帮忙看一下怎么回事，输出的结果怎么有时对有时差0.01呢？红色部分双精度浮点型转换为整型的时候怎么有时错误，比方说6.00就转换为5？？？
先谢谢了、、我看了老久也没看出来

补充：就是小数部分不对，整数部分正确。。

那怎么精确的输出几角几分啊？谢谢；

强制转换是不是有时候不精确啊？

虽然还是不行，，但依然很感谢、、我用sprintf()函数精确得到了小数部分，强制转换可能不精确，以后尽量避免使用，，

恩，，谢谢