// 输入一个1-4位整数、如果满足 a=i*i*i*i 等、即输出结果、若不满足则加以说明



#include "stdio.h"
#include "windows.h"



void main()
{
    int a,i,j;
    printf ( "Please input a:" );
   
    scanf ( "%d" , &a );
    for ( i = 0 ; i < a ; i ++ )
    {
        if ( a == i * i )
        {    printf (" a = %d * %d ",i,i );
            Sleep(1000);
            printf("\n");
            for ( j = 0;j < a / 2;j ++ )
                if ( i == j * j )
                {
                    printf (" a == %d * %d * %d * %d ",j,j,j,j);
                    printf("\n");
                    Sleep(1000);
                }
        }
        else
        {
            printf("无相同数相乘为a ");
            Sleep(1000);
            printf("\n");}
    }



}




有办法只让最后一个if语句只判断一次么?我弄了很久都没头绪 。