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题目是解ax*x+b*x+c=0的解，必须用bool solution (double a,double b,double c,double& x1,double& x2),输入a,b,c求解x1,x2.以下是我的程序
#include <iostream>
#include <cmath>
using namespace std;
bool solution (double a,double b,double c,double x1,double x2)
{
     double D,p;

    D=b*b-4*a*c;

    if (D<0)

    {  
           return   false;
    }
    if (D==0)

    {

    p=-b/(2*a);

    x1=p+sqrt(D)/(2*a);

    cout<<"方程有两个相同的实根。"<<endl;

    cout<<"x1=x2="<<x1<<endl;

    return true;
    }

    if (D>0)

    {

    p=-b/(2*a);

    x1=p+sqrt(D)/(2*a);

    x2=p-sqrt(D)/(2*a);

     cout<<"方程有两个不同的实根。"<<endl;

     cout<<"x1="<<x1<<endl<<"x2="<<x2<<endl;
      return true;}}
int main()
   
{    double a,b,c,x1,x2;
      cin>>a>>b>>c
      bool solution (a,b,c,&x1,&x2)
     cout<<"请输入3个数："<<endl;
       cout<<"方程为："<<a<<"x^2+"<<b<<"x+"<<c<<"=0"<<endl;
     if (bool=false)
           cout<<"方程无解!"<<endl;
     if (bool==true)
          cout<<"x1="<<x1<<";"<<"x2="<<x2;
      

我想问怎么返回，显示x1,x2的值，上面程序编译不过去！