编程，计算函数y的值。要求键盘接收自变量x的值，若x 的值不为零，则计算函数y的值并输出，再从键盘接收下一个x的值，……，直到x的值为零，则显示“Thank You，Bye!”，尔后结束程序，已知函数y与自变量x的关系为：y=3*x+10(0<x<100)
                                                                               x*x*x-20(x>=100)
# include<stdio.h>
void main()
{
int x,y;
printf("请输入x的值:",x);
scanf("%d",&x);
if(x>0 && x<100)
{y=3*x+10;
printf("y=%d",y);}
else if(x>=100)
{y=x*x*x-20;
printf("y=%d",y);}
else if(x==0)
printf("Thank you,Bye!\n");
}