#include<iostream.h>
#include<string.h>

int nextStudentID=0;
class StudentID
{
public:
    StudentID()
    {
        value=++nextStudentID;
        cout<<"Assigning student id"<<value<<endl;
    }
    ~StudentID()
    {
        --nextStudentID;
        cout<<"Destructing  id"<<value<<endl;
    }
protected:
    int value;
};

class Student
{
public:
    Student(char* pName="noName")
    {
        cout<<"Constructing student "<<pName<<endl;
        strcpy(name,pName);
        name[sizeof(name)-1]='\0';
    }
protected:
    char name[20];
    StudentID id;
};
int main()
{
    Student s("Marry");
    return 0;
}
运行结果为：Assigning student id 1
            Constructing student Marry
            Destructing id 1
我对此程序的执行顺序不太理解，请高手指点一下！

但是，在S对象空间中的结构，第一为name[20],第二为id,为什么在结果运行后先输出id ,后输出name呢？

谢谢！