#include <stdio.h>
#include <stdlib.h>
char *str3;
int main(void)
{
    char *str1 = "hello world";
    char str2[] = "hello world two";
    str3 = "hello world three";
    char *str4 = malloc(sizeof(char)*1024);
    if (str4 == NULL)
        return -1;
    str4 = "hello world four";
    printf("%x %s\n", &str1, str1);
    printf("%x %s\n", &str2, str2);
    printf("%x %s\n", &str3, str3);
    printf("%x %s\n", &str4, str4);
    return 0;
}

widon@widon-F3JR:/tmp$ ./a.out
bfe60164 hello world
bfe6016c hello world two
804a024 hello world three
bfe60168 hello world four

str1，str2都在栈空间分配，str3在静态存取区域，str4在堆吧，
可是str1，str2，str4分配地址是连续的啊

int main(void)
{
    char *str1 = "hello world";
    char str2[] = "hello world two";
    str3 = "hello world three";
    char *str4 = malloc(sizeof(char)*1024);
    if (str4 == NULL)
        return -1;
    str4 = "hello world four";
    char *str5 = "hello world five";
    printf("%x %x\n", &str1, str1);
    printf("%x %x\n", &str2, str2);
    printf("%x %x\n", &str3, str3);
    printf("%x %x\n", &str4, str4);
    printf("%x %x\n", &str5, str5);
    return 0;
}
widon@widon-F3JR:/tmp$ ./a.out
bfb97d70 8048660
bfb97d7c bfb97d7c
804a024 804866c
bfb97d74 804867e
bfb97d78 804868f

恩，我知道了，str1,str2,str4都是局部变量，都存在栈里面,str3存放在静态数据区
str1指向0x8048660也就是说hello world存放在0x8048660~0x804866B共12个字节
str3指向0x804866c也就是说hello world three存放在0x804866c~0x804867D共18个字节
str4指向0x804867e也就是说hello world four存放在0x804867e~0x804868e共17个字节
对吗？str1,str3,str4都指向一个连续的地址，应该在同一个区域吧，叫什么呢？