一本书中的例子，我想借用，可是编译出来总是出错，错误是error C2664: 'slgq' : cannot convert parameter 3 from 'double [11][11]' to 'double []'，请高手给我指点。
#include "math.h"
#include "stdio.h"

main()
{
    extern double slgq(double x[],double y[],double z[],int n,int m,double u,double v);
    int i,j;
    double u,v,w;
    static double x[11],y[11],z[11][11];
    for (i=0;i<=10;i++)
    {
        x[i]=0.1*i;y[i]=x[i];
    }
    for(i=0;i<=10;i++)
        for(j=0;j<=10;j++)
            z[i][j]=exp(-(x[i]-y[j]));
        printf("\n");
        u=0.35;v=0.65;
        w=slgq(x,y,z,11,11,u,v);
        printf("x=%7.3f,  y=%7.3f,  z(x,y)=%e\n",u,v,w);
        printf("\n");
}

double slgq(double x[],double y[],double z[],int n,int m,double u,double v)
{
    int ip,ipp,i,j,l,iq,iqq,k;
    double h,w,b[10];
    if (u<=x[0]) {ip=1;ipp=4;}
    else if(u>=x[n-1]) {ip=n-3;ipp=n;}
    else
    {
        i=l;j=n;
        while (((i-j)!=1)&&((i-j)!=-1))
        {
            l=(i+j)/2;
            if (u<x[l-1]) j=1;
            else i=l;
        }
        ip=i-3;ipp=i+4;
    }
    if (ip<1) ip=1;
    if (ipp>n) ipp=n;
    if (v<=y[0]) {iq=1;iqq=m;}
    else  if (v>=y[m-1]) {iq=m-3;iqq=m;}
    else
    {
        i=l;j=m;
        while (((i-j)!=1)&&((i-j)!=-1))
        {
            l=(i+j)/2;
            if (v<y[l-1]) j=1;
            else i=1;
        }
        iq=i-3;iqq=i+4;
    }
    if(iq<1) iq=1;
    if(iqq>m) iqq=m;
    for(i=ip-1;i<=ipp-1;i++)
    {
        b[i-ip+1]=0.0;
        for(j=iq-1;j=iqq-1;j++)
        {
            h=z[m*i+j];
            for (k=iq-1;k<=iqq-1;k++)
                if(k!=j) h=h*(v-y[k])/(y[j]-y[k]);
                b[i-ip+1]=b[i-ip+1]+h;
        }
    }
    w=0.0;
    for(i=ip-1;i<=ipp-1;i++)
    {
        h=b[i-ip+1];
        for (j=ip-1;j<=ipp-1;j++)
            if (j!=1) h=h*(u-x[j])/(x[i]-x[j]);
            w=w+h;
    }
    return(w);
}

谢谢各位了，按照sidooh的方法问题已解决。