#include <stdio.h>
                 struct s1{
                       char *s;
                       struct s1 *ptr;
             };
            struct s1 a[]={
                       {"efgh",a+1},
                       {"ijkl",a+2},
                       {"mnop",a}};
                 struct s1 *p=a;
                 void main( ) {
                       int i;
                       for(i=0;i<3;i++ )
                    printf({"%s %s %c %s\n",a.s,a.ptr->s,a.s++,
                           ++p++->ptr->s+1);
答案是fgh jkl e kl
      jkl nop k op
      nop fgh p gh
怎么会出现这样结果？

这是最近在做的一个题 谢楼上详细解答 可第二行输出kl nop  j op看不懂 按你所说 i=1 先算*a[1].s++ 先取a[1] 然后将a[1].s地址增1 第一个%s应该输出jkl啊