各位大虾
今天编了一个程序，经过几次修改，终于可以编译生成可执行文件了，但是在运行时又出问题了
出现了“ox00401810”指令引用的“ox33463280”内存。该内存不能为“read”
究竟怎么回事啊？
谢过各位大虾了
谢过所有看帖的人

我把源码粘出来
#include<iostream>
using std::cin;
using std::cout;
using std::endl;
int main()
{
int bYear[]={31,29,31,30,31,30,31,31,30,31,30,31};
int sYear[]={31,28,31,30,31,30,31,31,30,31,30,31};
cout<<"enter year,month,day:"<<endl;
int year,month,day;
int s1,s2,s,fact;
int i;
s1=(year-1)+((year-1)/4)-((year-1)/400);
cin>>year>>month>>day;
if(year%400&&year%4)
   for(;i<=(month-1);++i)
      {
      cout<<endl;
      s2=s2+bYear[i];
      }
   s2=s2+day;
if(year%400!=0&&year%4!=0)
{
     for(;i<=(month-1);++i)
   {
   s2+=sYear[i];
   }
   s2=s2+day;
}
s=s1+s2;
fact=s%7;
switch(fact)
{
   case 0:
      cout<<"today is sunday";
      break;
   case 1:
      cout<<"today is monday";
      break;
   case 2:
      cout<<"today is tuseday";
      break;
   case 3:
      cout<<"today is wednesday";
      break;
   case 4:
      cout<<"today is thurday";
      break;
   case 5:
      cout<<"today is friday";
      break;
   case 6:
      cout<<"today is saturday";
      break;
   default:cout<<"this program has bugs.";
}
return 0;
}        
 
 

还是不行啊

我觉得是数组在调用内存时失败造成的
有这种可能么？

经过大家的共同努力，我们成功了！下面的源代码是改好的
它的功能是计算任意一天是星期几
请大家分享
#include<iostream>
using std::cin;
using std::cout;
using std::endl;
int main()
{
int bYear[]={31,29,31,30,31,30,31,31,30,31,30,31};
int sYear[]={31,28,31,30,31,30,31,31,30,31,30,31};
cout<<"enter year,month,day:"<<endl;
int year,month,day;
int s1=0,s2=0,s=0,fact=0;
int i;
cin>>year>>month>>day;
s1=(year-1)+((year-1)/4)-((year-1)/100)+((year-1)/400);
if(year%400||year%4)
{
   for(i=0;i<=(month-1);++i)
      {
      s2=s2+bYear[i];
      }   
}
if(year%400!=0||year%4!=0)
{
     for(i=0;i<=(month-1);++i)
     {
        s2=s2+sYear[i];
     }
}
s2=s2+day;
s=s1+s2;
fact=s%7;
switch(fact)
{
   case 0:
      cout<<"today is sunday\n";
      break;
   case 1:
      cout<<"today is monday\n";
      break;
   case 2:
      cout<<"today is tuseday\n";
      break;
   case 3:
      cout<<"today is wednesday\n";
      break;
   case 4:
      cout<<"today is thurday\n";
      break;
   case 5:
      cout<<"today is friday\n";
      break;
   case 6:
      cout<<"today is saturday\n";
      break;
   default:cout<<"this program has bugs.";
}
return 0;
}      
谢谢大家！！！！！！！！！！！

[ 本帖最后由 loookc 于 2009-10-17 13:16 编辑 ]

应该不用
因为根据算“任意一天是星期几的算法看来”fact是不会为负的

经过测试，上面的程序有误

改了的
#include<iostream>
using std::cin;
using std::cout;
using std::endl;
int main()
{
int bYear[]={31,29,31,30,31,30,31,31,30,31,30,31};
int sYear[]={31,28,31,30,31,30,31,31,30,31,30,31};
cout<<"enter year,month,day:"<<endl;
int year,month,day;
int s1=0,s2=0,s=0,fact=0;
int i;
cin>>year>>month>>day;
s1=(year-1)+((year-1)/4)-((year-1)/100)+((year-1)/400);
     if((year%4==0)&&(year%100!=0)||(year%400==0))
     {
         for(i=0;i<=(month-2);++i)
         {
         s2=s2+bYear[i];
         }   
     }
     else
     {  
         for(i=0;i<=(month-2);++i)
         {
         s2=s2+sYear[i];
         }
     }
      
s2=s2+day;
s=s1+s2;
fact=s%7;
switch(fact)
{
   case 0:
      cout<<"this day is sunday\n";
      break;
   case 1:
      cout<<"this day is monday\n";
      break;
   case 2:
      cout<<"this day is tuseday\n";
      break;
   case 3:
      cout<<"this day is wednesday\n";
      break;
   case 4:
      cout<<"this day is thurday\n";
      break;
   case 5:
      cout<<"this day is friday\n";
      break;
   case 6:
      cout<<"this day is saturday\n";
      break;
   default:cout<<"this program has bugs.";
}
return 0;
}      

#include<iostream>
using std::cin;
using std::cout;
using std::endl;
int main()
{
int bYear[]={31,29,31,30,31,30,31,31,30,31,30,31};
int sYear[]={31,28,31,30,31,30,31,31,30,31,30,31};
cout<<"enter year,month,day:"<<endl;
int year,month,day;
int s1=0,s2=0,s=0,fact=0;
int i;
cin>>year>>month>>day;
s1=(year-1)+((year-1)/4)-((year-1)/100)+((year-1)/400);
     if((year%4==0)&&(year%100!=0)||(year%400==0))
     {
         for(i=0;i<=(month-2);++i)
         {
         s2=s2+bYear[i];
         }   
     }
     else
     {  
         for(i=0;i<=(month-2);++i)
         {
         s2=s2+sYear[i];
         }
     }
      
s2=s2+day;
s=s1+s2;
fact=s%7;
switch(fact)
{
   case 0:
      cout<<"this day is sunday\n";
      break;
   case 1:
      cout<<"this day is monday\n";
      break;
   case 2:
      cout<<"this day is tuseday\n";
      break;
   case 3:
      cout<<"this day is wednesday\n";
      break;
   case 4:
      cout<<"this day is thurday\n";
      break;
   case 5:
      cout<<"this day is friday\n";
      break;
   case 6:
      cout<<"this day is saturday\n";
      break;
   default:cout<<"this program has bugs.";
}
return 0;
}      
大家再看看