#include <iostream>
unsigned long left(unsigned long num,unsigned ct);
char *letf(const char *str,int n=1);
int main()
{
    using namespace std;
    char *trip="hawail!! ";
    unsigned long n=12345678;
    int i;
    char *temp;

    for(i=1;i<10;i++)
    {
        cout<<left(n,1)<<endl;
        temp=left(trip,i);
        cout<<temp<<endl;
        delete[]temp;
    }
    return 0;
}
unsigned long letf(unsigned long num,unsigned ct)
{
    unsigned diguts=1;
    unsigned n=num;

    if(ct==0||num==0)
        return 0;
    while(n/=10)
        diguts++;
    if(diguts>ct)
    {
        ct=diguts-ct;
        while(ct--)
            num/=10;
            return num;
    }
    else
    { return num;}
}

char *letf(const char * str,int n)
{
    if(n<0)
        n=0;
    char *p=new char(n+1);
    int i;
    for(i=0;i<n&&str[i];i++)
        p[i]=str[i];
    while(i<=n)
        p[i++]='\0';
    return p;
错误提示：
}:\c++程序\zy_8_10\10.cpp(15) : error C2665: 'left' : none of the 2 overloads can convert parameter 1 from type 'char *'
Error executing cl
希望高手帮我解答

[ 本帖最后由 蜗牛进程 于 2009-11-2 19:31 编辑 ]

谢谢版主~我知道了