程序什么地方出错了? - ASP技术论坛

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程序什么地方出错了?

<SCRIPT language=javascript>
function showing() {
newX = window.event.x + document.body.scrollLeft
newY = window.event.y + document.body.scrollTop
menu = document.all.itemopen
if ( menu.style.display == ""){
menu.style.display = "none" }
else {
menu.style.display = ""}

menu.style.pixelLeft = newX + 50
menu.style.pixelTop = newY

document.write("<table width='100' height='100' border='0' cellpadding='0' cellspacing='0' class='box' id='itemopen' style='display:none'>")
document.write("<tr><td><img src='showing.asp' width='100' height='100'></td></tr> ")

document.write("</table>")
}
</SCRIPT>

[此贴子已经被作者于2006-1-10 11:19:44编辑过]

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第 2 楼

得分:0

下面是我全部的代码: 我想实现当点击表格中间一行是,调用showing()函数,问题是,调用函数以后,图片也出来了,但是把原来的表格给覆盖掉了.这是为什么?
test.asp
*****************************************
<html>
<head>
<title>图片显示</title>
<style type="text/css">

</style>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
</head>

<body bgcolor="#fef4d9">
<SCRIPT language=javascript>
function showing() {
document.write("<style>")
document.write(".box { font: 9pt '宋体'; position: absolute; background: #ffffff }")
document.write("</style>")
document.write("<table width='100' height='100' border='0' cellpadding='0' cellspacing='0' class='box' id='itemopen' style='display:none'>")
document.write("<tr><td><img src='showing.asp' width='100' height='100'></td></tr> ")

document.write("</table>")
newX = window.event.x + document.body.scrollLeft
newY = window.event.y + document.body.scrollTop
menu = document.all.itemopen
if ( menu.style.display == ""){
menu.style.display = "none" }
else {
menu.style.display = ""}

menu.style.pixelLeft = newX + 50
menu.style.pixelTop = newY

}
</SCRIPT>
<table width="44%" height="173" border="1" align="center" cellpadding="1" cellspacing="1">
<tr>
<td> </td>
</tr>
<tr>
<td align="center" onClick="showing()"> </td>
</tr>
<tr>
<td> </td>
</tr>
</table>

</body>
</html>
******************************************************
showing.asp
*****************************************************

<%
set rec=server.createobject("ADODB.recordset")
sql="select picture from kqxxb where mkid=100502"
rec.open sql,conn
Response.ContentType="image/*"
Response.BinaryWrite rec("picture").getChunk(7500000)
rec.close
set rec=nothing
set conn=nothing
%>
showing.asp是为了实现从数据中调用二进制图片. 测试是可以找个图片代替

[此贴子已经被作者于2006-1-10 11:38:50编辑过]

第 3 楼

得分:0

以下是引用rainic在2006-1-10 11:42:00的发言：
这想这个可以帮到你吧
[CODE]<html>
<head>
</head>
<body>
<form action="" method="post" enctype="multipart/form-data" name="form1">
<input name="attach" type="file" onchange="javascript:ShowImg(this.value);" onKeyDown="javascript:return(false);" size="20">
<script language="JavaScript">
function ShowImg(src)
{
document.getElementById("imgDiv").innerHTML="图片预览：<br><img id='imgObj' onerror='javascript:GetError()' onload='javascript:GetSize()' src='file:///" + src + "'>";
}
function GetSize()
{
var width,height;
var imgObj=document.getElementById("imgObj");
width=imgObj.width;
height=imgObj.height;
document.getElementById("err_msg").innerHTML="图片大小(宽×高):<font color=red>" + width + "×" + height + "</font>";
if(width>164){
imgObj.width=164;
imgObj.height=imgObj.height/(imgObj.width/164);
}
}
function GetError()
{
document.getElementById("err_msg").innerHTML="图片大小(宽×高):<font color=red>NaN</font>";
document.getElementById("imgDiv").innerHTML="";
document.getElementById("err_msg").innerHTML="图片文件不存在或格式错误！"
}
</script>
<div id="imgDiv" align="center"></div>
<div id="err_msg" align="center"></div>
</form>
</body>
</html>[/CODE]

还是没弄明白我的意思,我现在已经把图片以二进制形式传到sql数据中了,现在我要读取这些图片,读取的方式是,当点击中间一行时,调用showing函数,使图片以宽100,高100大小显示,再次点击中间行,图片消失

第 4 楼

得分:0

谢谢了,我在实施