<form name="form1" action="12.asp" method="post">
            查 询：<input name="cc"  class="input" /><input type="submit" value="搜 搜" />
</form>
<%
      if request.ServerVariables("REQUEST_METHOD")="post" then
          cc=request.Form("cc")
         response.write("cc")
       else
        response.write("bb")
       end if
%>

12.asp是这个文件的文件名  我想不点击表单按钮    就输出bb     点击表单按钮   就输出表单按钮文本框里的内容        我这思路是不是错了   怎么整不出效果来呢       谢谢

<form name="form1" action="12.asp" method="post">
            查 询：<input name="cc"  class="input" /><input type="submit" value="搜 搜" />
</form>
<%
      if request.ServerVariables("REQUEST_METHOD")="post" then
          cc=request.Form("cc")
         response.write(cc)
       else
        response.write("bb")
       end if
%>

路过的进来看看  给点意见撒