#include <stdio.h>
double power (int, int);
int main (void)
{
        int count, zz;
        double result;

        printf ("请输入要处理的数:\n");
        scanf ("%d", &count);
        printf ("请输入它的指数:\n");
        scanf ("%d", &zz);

        result = power (count,zz);
        printf ("%.3f为所求!");
}

double power (int count, int zz)
{
        double result;
        int i;

        if (count == 0)
                return  0;
        if (zz == 0)
                return  1;
        if (zz > 0)
        {
                for (i = 0; i < zz-1; i++)
                        count *= count;
                result = count;
        }
        else
        {
                for (i = 0; i< -zz-1; i++)
                        count *= count;
                result = 1.0/count;
        }
        return result;
}

我是在linux下编写的,可以显示出来.
问题是出在输入不了数据.
请您运行下式式/?

就是输入两个double类型的数,将大数赋给小数.

恩恩...谢谢 1楼 的 !!!!