#include<stdio.h>
#include<math.h>
void main()
{
  float x,x0,x1,x2,y;
  float fun(float);//函数编写
  
  float fun(float x)
  {
     y=x*(x*(2x-4)+3)-6;
     return(y);
  }
x1=-10,x2=10;
do
{
  x0=(x1+x2)/2;//必要时修改y=fun(x0)
  if(fun(x0)<0)
      x1=x0;
  else
      x2=x0;
}while(fabs(x1-x2)>=1e-5);
printf("the root of this equation is %f",x0);
}
报错搜过原因  还是看不懂

这是一个用二分法求2x^3-4x^2+3x-6=0  在(-10,10)之间的根   
报错是D:\jude\computer\编程\works\第六章\习题6.13\Cpp1.cpp(9) : error C2601: 'fun' : local function definitions are illegal
D:\jude\computer\编程\works\第六章\习题6.13\Cpp1.cpp(10) : error C2059: syntax error : 'bad suffix on number'
Error executing cl.exe.

改正过来了 谢谢大家  
初学 一些细节掌握不好……  谢谢大家的指点

#include<stdio.h>
#include<math.h>
void main()
{
  float x0,x1,x2;
 float fun(float x);
  x1=-10,x2=10;
do
{
  x0=(x1+x2)/2;
  if(fun(x0)<0)
      x1=x0;
  else
      x2=x0;
}while(fabs(x1-x2)>=1e-5);
printf("the root of this equation is %f\n",x0);
}
  float fun(float x)
  {
     float y;
     y=x*(x*(2*x-4)+3)-6;
     return(y);
  }

谢谢