又经过一番努力终于编出来了，剩下的就是美化了，呵呵，上代码。


#include<stdio.h>
void main()
{
    char ch,ch1,ch2;
    for(;;)
    {
        printf("请输入您的种族。天族t，魔族m:");
        ch1=getchar();
        getchar();
        if(ch1=='m')
        {
            printf("您是魔族，请输入您要转化为天族文字的内容：\n");
            do
            {
                ch=getchar();
                if(ch>=65&&ch<=71||ch>=97&&ch<=103)
                {
                    if(ch%4==0||ch%4==1)
                        printf("%c",ch+21);
                    else if(ch%4==2||ch%4==3)
                        printf("%c",ch+17);
                }
                else if(ch>=72&&ch<=90||ch>=104&&ch<=122)
                {
                    if(ch%4==0||ch%4==1)
                        printf("%c",ch-5);
                    else if(ch%4==2||ch%4==3)
                        printf("%c",ch-9);
                }
                else
                    printf("%c",ch);
            }while(ch!='\n');
            printf("\n");
        }
        else if(ch1=='t')
        {
            printf("您是天族，请输入您要转化为魔族文字的内容：\n");
            do
            {
                ch=getchar();
                if(ch>=65&&ch<=71||ch>=97&&ch<=103)
                {
                    if(ch%2==0)
                        printf("%c",ch+20);
                    else if(ch%2==1)
                        printf("%c",ch+18);
                }
                else if(ch>=72&&ch<=90||ch>=104&&ch<=122)
                {
                    if(ch%2==0)
                        printf("%c",ch-6);
                    else if(ch%2==1)
                        printf("%c",ch-8);
                }
                else
                    printf("%c",ch);
            }while(ch!='\n');
            printf("\n");
        }
        else
            printf("您不属于Aion种族，请重新输入\n");
        printf("是否继续 y or n :");
        ch2=getchar();
        getchar();
        if(ch2=='n')
            break;
    }
}

[[it] 本帖最后由 soky 于 2009-7-25 02:14 编辑 [/it]]

一般都是要把自己说的话转化给别人看。