图形界面上有一个按钮，当鼠标移到按钮上时按钮掩藏，当鼠标离开按钮时按钮显示。下面是我的代码，不过不是我想要的效果，大侠们帮忙改正一下，最好是先说下思路，说一下我的思路为什么错了。

import java.awt.*;
import java.awt.event.*;
public class shu145_8 extends Frame implements WindowListener{
   Button b;
   Panel p;

 public shu145_8(String title){
   super(title);
   b=new Button("按钮");
   p=new Panel();
   p.add(b,"Center");
   add(p);
   addWindowListener(this);
   b.addMouseListener(new MouseHandler());
}
   public static void main(String args[]){
     shu145_8 me=new shu145_8("鼠标");
     me.setSize(200,200);
     me.setVisible(true);
}

 public void windowClosing(WindowEvent e){
   System.exit(0);  

 }

 public void windowClosed(WindowEvent e){}

 public void windowDeactivated(WindowEvent e){}

 public void windowActivated(WindowEvent e){}

 public void windowIconified(WindowEvent e){}

 public void windowDeiconified(WindowEvent e){}

 public void windowOpened(WindowEvent e){}
class MouseHandler implements MouseListener{

 public void mouseClicked(MouseEvent e){}

 public void mousePressed(MouseEvent e){}

 public void mouseReleased(MouseEvent e){}

 public void mouseExited(MouseEvent e){
        b.setVisible(true);
}

 public void mouseEntered(MouseEvent e){
         b.setVisible(false);
}
}
}

如果我在开始就按钮掩藏
b.setVisible(false);
然后再运行，效果是鼠标到按钮上就消失了，不过鼠标离开按钮时，按钮也不显示出来了，

我有听说是awt不支持双缓冲，所以有闪屏的情况。
谢谢你们的解答，