#include<stdio.h>
#define fundlen 50
struct funds{
             char bank[fundlen];
             double bankfund;
             char save[fundlen];
             double savefund;
            };
double sum( struct funds * );
char my(struct funds *);
int say(int x,int y);
int main(void)
{//struct funds *e;
 int a=4,b=5;
 struct funds stan={
                    "gar",
                    3024.72,
                    "luck",
                    9237.11
                    };
printf("%f\n",sum(&stan));
printf("%s\n",my(&stan));/*输出有错误*/
//e=&stan;
//printf("%s\n",e->bank);
printf("%d\n",say(a,b));
return 0;
}
double sum( struct funds *p)
{return(p->bankfund+p->savefund);
}
char my(struct funds *e)
{return (e->bank);
}
int say(int x,int y)
{return (x+y);
}

输出结果可以了,不过请教下
char my(struct funds *e)
{return (e->bank);
}这么是返回一个指针,是bank数组的首地址吗
double sum( struct funds * );为什么不改成double *sum( struct funds * );就可以



[ 本帖最后由 mxh2008 于 2010-5-13 12:58 编辑 ]

return(p->bankfund+p->savefund);返回的就是一个double型变量,这个清楚.
return (e->bank);返回的是一个指针变量,还不是很清楚

各位帮忙详细讲解下
是不是bank是个数组,return (e->bank);返回就是一个指针