表單上有一個 pictureBox 一個 Button
picturBox 有三張圖片用亂數方式選取
事件則寫在按鈕下: 即按一下按鈕時用亂數值抽選一張圖片並顯示

目前是不成功的, 想請各位高手幫助

語法:

public void Random()
        {
            System.Random ran1 = new Random();
            int i = ran1.Next(0, 3);
            switch (i)
            {
                case 0:
                    {
                        i = 0;
                        pictureBox1.Show();
                        pictureBox1.Load(@"Resources\1.gif");
                        break;
                    }
                case 1:
                    {
                        i = 1;
                        pictureBox1.Show();
                        pictureBox1.Load(@"Resources\2.gif");
                        break;
                    }
                case 2:
                    {
                        i = 2;
                        pictureBox1.Show();
                        pictureBox1.Load(@"Resources\3.gif");
                        break;
                    }
            }
        }

        private void button1_Click(object sender, EventArgs e)
        {
            pictureBox1.Show();
             Random();
        }

此問題已解決  謝謝