编函数int find（char s[],char t[]）,该函数在字符串s中查找字符串t，如果找到，则返回字符串t在字符串s中的位置（整数值）；否则返回－1。注意：用数组方式及两重循环来实现该函数。仅在find的花括号中填写若干句。

#include<iostream.h> #include<string> int find(char s[],char t[]); const int MAXLINE=256; int main() {char source[MAXLINE],target[MAXLINE]; cout<<"Please in put a string for searching:\n"; cin.getline(source,MAXLINE); cout<<"Please input a string you want to find:\n"; cin.getline(target,MAXLINE); int intPos=find(source,target); if(inPos>=0) cout<<"Find it.The target string is at index"<<inpos<<"of the source string\n"; else cout <<"Not finding it.\n"; return 0; } int find(char s[],char t[]) { }

试了很多次都不成功，又没有答案·········

帮帮忙········

呵呵·······

这是我最后写的····

乱七八糟····唉······

#include<iostream.h> #include<string> int find(char s[],char t[]); const int MAXLINE=256; int main() {char source[MAXLINE],target[MAXLINE]; cout<<"Please in put a string for searching:\n"; cin.getline(source,MAXLINE); cout<<"Please input a string you want to find:\n"; cin.getline(target,MAXLINE); int intPos=find(source,target); if(intPos>=0) cout<<"Find it.The target string is at index"<<intPos<<"of the source string\n"; else cout <<"Not finding it.\n"; return 0; } int find(char s[],char t[]) {int len1=strlen(s),len2=strlen(t); int i=0,count=0; char *p=t; for(int j=0;j<len2;j++) {for(;i<len1;i++) if(char s[i]==p) count++;

} p++; return (i-count+1); else return -1; }

无论输入什么，都说找不到喔·······

而且他说用2重循环········