对于一个已经填充好的数组(没有填充满)
怎么把这个数组逆序输出啊???
我是这样做的:
char c[100];
char *rs = c;
//往里放些值;(不放满)
//然后要按上面输入的逆序输出;
char *ch = strrev(c);
while(*ch)
{
    cout <<*ch;
    ch ++;
}
//为什么不行啊??

#include<iostream>
using namespace std;
void main()
{
    _int64 m, n, tmp, rs;
    while(scanf("%I64d%I64d", &m, &n))
    {
        char c[100];
        char *ch = c;
        rs = m - n;
        int i = 0;
        while((tmp = rs/10) > 0)
        {
            if(3 == i)
            {
                *ch = ',';
//                cout <<*ch;
                ch ++;
                i = 0;
            }
            *ch = rs - tmp*10 + 48;
//            cout <<*ch;
            ch ++;
            i ++;
            rs = tmp;
        }
        if(i == 3) 
        {
            *ch = ',';
//            cout <<*ch;
            ch ++;
        }
        *ch = rs + 48;
//        cout <<*ch;
        char *cc = strrev(c);
        while(*cc)
        {
            cout <<*cc - 48;
            cc ++;
        }
        printf("\n");
    }
}#include<iostream>
using namespace std;
void main()
{
    _int64 m, n, tmp, rs;
    while(scanf("%I64d%I64d", &m, &n))
    {
        char c[100];
        char *ch = c;
        rs = m - n;
        int i = 0;
        while((tmp = rs/10) > 0)
        {
            if(3 == i)
            {
                *ch = ',';
//                cout <<*ch;
                ch ++;
                i = 0;
            }
            *ch = rs - tmp*10 + 48;
//            cout <<*ch;
            ch ++;
            i ++;
            rs = tmp;
        }
        if(i == 3) 
        {
            *ch = ',';
//            cout <<*ch;
            ch ++;
        }
        *ch = rs + 48;
//        cout <<*ch;
        char *cc = strrev(c);
        while(*cc)
        {
            cout <<*cc - 48;
            cc ++;
        }
        printf("\n");
    }
}