我写的是一个不能称作游戏的游戏：电脑随机产生数字，使用者输入0-99个数字猜测，电脑给予提示，直到猜中，然后询问是否再play一次。问题就出在这。代码如下：
#include <stdlib.h>
#include <stdio.h>
void main()
{
     int result,guess;
     char again;
     game:  srand(time(NULL));
            result=rand()%100;
            play: printf("Please input a number which you think is lucky(0-99):");
                  scanf("%d",&guess);
                  if(guess<result)
                  {
                         printf("Your number is small.Please try again.\n");
                             goto play;
                  }
                  else if(guess>result)
                  {
                         printf("Your number is large.Please try again.\n");
                         goto play;
                     }
                  else
                  {
                         printf("You are right.Congratulations!\n");
                            printf("Do you want to play again?(Y or N):");
                         again=getchar();
                         again=getchar();
                         if(again=='Y')  goto game;
                     }
}
注意倒数第4 5排，用了2行again=getchar(); 而程序只执行了1行，更诡异的是，如果只写一行again=getchar(); 程序就直接跳过 然后级结束了；更更诡异的是，如果不是验证输入  Y 或 N  而是 1 或 0的话  用scanf("%d",&again); 的话 （当然 变量申明again 为 int型）  只需要一行，程序就能够顺利的进行···各位前辈，各位同辈···这是为什么捏··   （getchar()用scanf("%c",&again);代替有同样的问题）

寝室12点要断网了 先感谢2楼了来 再学习·····