输入一行字符，分别统计出其中英文字母、空格、数字和其他字符的个数。我的代码如下：

main()
{
    char c[100];
    printf("Please input a string less than 100 words:");
    scanf("%s",c);
    int i, alphabet=0, number=0, space=0, others=0;
    for ( i=0; i<100; i++ )
    {
        if (c[i]==32)
            space++;
         else if (c[i]>=48 && c[i]<=57)
            number++;
         else if(c[i]>=65 && c[i]<=90  ||  c[i]>=97 && c[i]<=122)
            alphabet++;
        else others++;
    }
    printf("The string has %d alphabets, %d numbers, % spaces and %d other character.\n", alphabet,number,space,others);
}

一编译，就出现如下错误信息：
expression syntax in function main
菜鸟请高手解决下，谢谢！看在我自学C、自主编的勇气上~~~