题目：
  两个乒乓球队进行比赛，各出3人，甲队为A,B,C，3人，乙队为X,Y,Z，3人。已抽签觉定比赛名单，A说他不和X比，C说他不和X,Z比。请编程序找出三对赛手的名单。
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 我这有个已经编号的。征求其他答案。编的简单易懂就行了。
#include"stdio.h"
#include"conio.h"
void mian()
{
char i,j,k;
for (i='x';i<='z';i++;)
 {
  if (i!=j)
  for(k='x';k<='z';k++)
   {
     if(i!=k&&j!=k)
      {
        if(i!='x'&&k!='x'&&k!='z')
         printf("order is a --%c\tb--%c\tc--%c\n",i,j,k);
       }
     }
  }
}

Maybe you are right,I should do it by myself.

Thanks!

[[it] 本帖最后由 单向路 于 2008-6-28 13:11 编辑 [/it]]

But I want to know  why you ask me that question ?
There are some users do it like that,why don't you say that?
Is the question of  my article title?

恩 确实错了  少了一个for循环
呵呵  多谢提醒