单击确定的时候
弹出错误

'查询的值与目标字段中的数目不同'
 
我看了一下数据表
是一样的啊?
这是怎么回事 啊?

protected void Button1_Click(object sender, EventArgs e)
    {

        {
            try
            {
                myconn = DB.CreateDB();
                string addurl = Request["TxtAddurl"].ToString();
                string title = FunStr(this.TxtTitle.Text);
                //string content = FunStr(this.TxtContent.Text);
                //string ptype = Request.QueryString["action"].ToString();
                string FileName = myFile.Value;
                HttpPostedFile UpFile = myFile.PostedFile; //获取对由客户端指定的上传文件的访问
                FileLength = UpFile.ContentLength;//获取上传文件的字节大小
                if (FileLength == 0)
                {
                    myconn.Open();
                    OleDbCommand cmd1 = new OleDbCommand("insert into link(title,addurl,picture) values('" + title + "','" + addurl + "')", myconn);
                    cmd1.ExecuteNonQuery();
                    Response.Write("<script>alert('数据添加成功');window.location.href='Admin_LinkAdd.aspx'</script>");
                    myconn.Close();
                }
                else
                {
                    string exName = FileName.Substring(FileName.LastIndexOf(".") + 1).ToUpper();//截取图片的后缀名
                    if (exName == "JPG" || exName == "BMP" || exName == "GIF")//判断图片的类型
                    {
                        if (FileLength > 204800)//判断图片是否大于200k（根据自己的需要判断大小）
                        {
                            Response.Write("<script>alert('对不起，图片大小不能大于200K');window.location.href='Admin_LinkAdd.aspx'</script>");
                            return;
                        }
                        else
                        {
                            string ImageName = DateTime.Now.ToString("yyyyMMddhhmmssfff") + "." + exName;//图片名称设置为保存的时间
                            Byte[] FileByte = new Byte[FileLength]; //图象文件储存到数组  
                            Stream ObjectStream = UpFile.InputStream;//建立数据流对像,获取一个 Stream 对象，该对象指向一个上载文件，以准备读取该文件的内容。

                            ObjectStream.Read(FileByte, 0, FileLength); //读取图象文件数据
                            string StrSql = "Insert Into link(title,addurl,picture) Values(values('" + title + "','" + addurl + "',@ImageName)";
                            OleDbCommand Cmd = new OleDbCommand(StrSql, myconn);
                            //Cmd.Parameters.Add("@Image",OleDbType.Binary, FileLength).Value = FileByte;
                            Cmd.Parameters.Add("@ImageName", OleDbType.VarChar, 100).Value = ImageName;
                            myconn.Open();
                            this.myFile.PostedFile.SaveAs(Server.MapPath("/Upload") + "\\" + ImageName);
                            Cmd.ExecuteNonQuery();
                            myconn.Close();
                            Response.Write("<script>alert('数据添加成功');window.location.href='Admin_LinkAdd.aspx'</script>");
                        }
                    }
                    else
                    {
                        Response.Write("<script>alert('对不起，请选择正确的的图片！');window.location.href='Admin_LinkAdd.aspx'</script>");
                        return;
                    }
                }


            }
            catch (Exception ex)
            {
                Response.Write("<script>alert('" + ex.Message + "')</script>");
            }
        }


代码是这样的

调试的时候到 myconn.Close();
就跳到下面了啊出现错误提示
'没有找到upload的衍射路径'
是怎么回事啊?